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nordsb [41]
3 years ago
8

If the forces on an object are balanced the resultant force is equal to zero true false

Physics
1 answer:
nordsb [41]3 years ago
4 0

Answer:

If the forces are balanced, the resultant force is zero. If the forces on an object are unbalanced, this is what happens: a stationary object starts to move in the direction of the resultant force. a moving object changes speed and/or direction in the direction of the resultant force.

Explanation:

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A uniformly charged, one-dimensional rod of length L has total positive charge Q. Itsleft end is located at x = ????L and its ri
GREYUIT [131]

Answer:

|\vec{F}| = \frac{1}{4\pi\epsilon_0}\frac{qQ}{L}(\ln(L+x_0)-\ln(x_0))

Explanation:

The force on the point charge q exerted by the rod can be found by Coulomb's Law.

\vec{F} = \frac{1}{4\pi\epsilon_0}\frac{q_1q_2}{r^2}\^r

Unfortunately, Coulomb's Law is valid for points charges only, and the rod is not a point charge.

In this case, we have to choose an infinitesimal portion on the rod, which is basically a point, and calculate the force exerted by this point, then integrate this small force (dF) over the entire rod.

We will choose an infinitesimal portion from a distance 'x' from the origin, and the length of this portion will be denoted as 'dx'. The charge of this small portion will be 'dq'.

Applying Coulomb's Law:

d\vec{F} = \frac{1}{4\pi\epsilon_0}\frac{qdq}{x + x_0}(\^x)

The direction of the force on 'q' is to the right, since both charges are positive, and they repel each other.

Now, we have to write 'dq' in term of the known quantities.

\frac{Q}{L} = \frac{dq}{dx}\\dq = \frac{Qdx}{L}

Now, substitute this into 'dF':

d\vec{F} = \frac{1}{4\pi\epsilon_0}\frac{qQdx}{L(x+x_0)}(\^x)

Now we can integrate dF over the rod.

\vec{F} = \int{d\vec{F}} = \frac{1}{4\pi\epsilon_0}\frac{qQ}{L}\int\limits^{L}_0 {\frac{1}{x+x_0}} \, dx = \frac{1}{4\pi\epsilon_0}\frac{qQ}{L}(\ln(L+x_0)-\ln(x_0))(\^x)

4 0
3 years ago
Why do remote controls for TV’s use infrared waves to communicate?
Delvig [45]

Answer:  An IR remote (also called a transmitter) uses light to carry signals from the remote to the device so it can be controlled. It emits pulses of invisible infrared light that correspond to specific binary codes. These codes represent commands, such as power on, volume up, or channel down.

Explanation:

3 0
3 years ago
Can we use momentum to see how fast the earth is going?
Kisachek [45]

Yes, if we know the Earth's mass

Explanation:

The momentum of an object is a vector quantity given by the equation

p=mv

where

m is the mass of the object

v is its velocity

In this case, we are asked if we can find the velocity of the Earth by starting from its momentum. Indeed, we can. In fact, we can rewrite the equation above as

v=\frac{p}{m}

Therefore, if we know the momentum of the Earth (p) and we know its mass as well (m), we can solve the formula to find the Earth's velocity.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

6 0
4 years ago
What is the wavelength of a wave with a frequency of 466 Hz and a speed of
Volgvan

Answer:

<h3>The answer is option B</h3>

Explanation:

The wavelength of a wave can be found by using the formula

\lambda =  \frac{c}{f} \\

where

c is the speed of the wave

f is the frequency

From the question

c = 343 m/s

f = 466 Hz

We have

\lambda =  \frac{343}{466} \\  =  0.73605150...

We have the final answer as

<h3>0.74 m</h3>

Hope this helps you

4 0
3 years ago
A jet airliner moving initially at 548 mph
sasho [114]

Let's choose the "east" direction as positive x-direction. The new velocity of the jet is the vector sum of two velocities: the initial velocity of the jet, which is

v_1 =548 mph along the x-direction

v_2 = 343 mph in a direction 67^{\circ} north of east.

To find the resultant, we must resolve both vectors on the x- and y- axis:

v_{1x}= 548 mph

v_{1y}=0

v_{2x} = (343 mph)( cos 67^{\circ})=134.0 mph

v_{2y} = (343 mph)( sin 67^{\circ})=315.7 mph

So, the components of the resultant velocity in the two directions are

v_{x}=548 mph+134 mph=682 mph

v_{y}=0 mph+315.7 mph=315.7 mph

So the new speed of the aircraft is:

v=\sqrt{v_x^2+v_y^2}=\sqrt{(682 mph)^2+(315.7 mph)^2}=751.5 mph

3 0
3 years ago
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