Answer: 14. 49 m
Explanation:
We can solve this problem with the following equations:
(1)
(2)
Where:
is the horizontal distance between the cannon and the ball
is the cannonball initial velocity
since the cannonball was shoot horizontally
is the time
is the final height of the cannonball
is the initial height of the cannonball
is the acceleration due gravity
Isolating
from (2):
(3)
(4)
(5)
Substituting (5) in (1):
(6)
Finally:
Answer:
130 km at 35.38 degrees north of east
Explanation:
Suppose the HQ is at the origin (x = 0, y = 0)
So the coordinates of the helicopter after the 1st flight is


After the 2nd flight its coordinate would be:


So in order to fly back to its HQ it must fly a distance and direction of
north of east
Answer:
H = 34.43 m
Explanation:
Given that,
Initial speed of the object, u = 30 m/s
The angle of projection, 
We need to find the maximum height reached by the object. Let it is H. Using the formula for maximum height reached by the projectile.

So, the maximum height reached by the object is 34.43 m.
Answer:
a set up where current flows without a voltage difference
Explanation:
because a circuit is a set up of different components, and throughout the circuit the voltage is the same, even with more components
Altered means to change something.