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dalvyx [7]
3 years ago
10

Cite the phases that are present and the phase compositions for the following alloys: (a) 15 wt% Sn - 85 wt% Pb at 100 o C. (b)

1.25 kg of Sn and 14 kg Pb at 200 o C
Engineering
1 answer:
Novosadov [1.4K]3 years ago
6 0

Answer:

a)  ∝  and β

   The phase compositions are :

    C_{\alpha } = 5wt% Sn - 95 wt% Pb

    C_{\beta } =  98 wt% Sn - 2wt% Pb

b)

The phase is; ∝  

The phase compositions is;   82 wt% Sn - 91.8 wt% Pb

Explanation:

a) 15 wt% Sn - 85 wt% Pb at 100⁰C.

The phases are ; ∝  and β

The phase compositions are :

C_{\alpha } = 5wt% Sn - 95 wt% Pb

C_{\beta } =  98 wt% Sn - 2wt% Pb

b) 1.25 kg of Sn and 14 kg Pb at 200⁰C

The phase is ; ∝  

The phase compositions is;  82 wt% Sn - 91.8 wt% Pb

Csn = 1.25 * 100 / 1.25 + 14 = 8.2 wt%

Cpb = 14 * 100 / 1.25 + 14 = 91.8 wt%

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Answer:

All 3 principal stress

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Explanation:

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internal pressure pi = 150 kpa = 150 x 10³

torque t = 100 Nm

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∂1 = 150x10³x0.075/2x0,0001

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∂2 = 150x10³x75/4x0.1

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T = 16x100/(πx75x10³)²

∂1,2 = 1/2[(56.25+28.12) ± √(56.25-28.12)² + 4(1.207)²]

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∂1 = 1/2[84.37+28.33]

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∂2 = 1/2[84.37-28.33]

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3 years ago
All of the dimensions on an aircraft drawing are_________<br> to the bottom of the drawing.
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2 years ago
A small pad subjected to a shearing force is deformed at the top of the pad 0.08 in. The height of the pad is 1.38 in. What is t
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Answer:

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Step1

Given:

Height of the pad is 1.38 in.

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Step2

Shear strain is calculated as follows:

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Thus, the shear strain is 0.05797 rad.

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