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2 years ago

9

3. When performing overhead work on scaffolding, what protective measures must be taken to prevent objects

1 answer:

hjlf2 years ago

7 0

Answer:

Toeboards, debris nets, or canopies

Explanation:

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A typical aircraft fuselage structure would be capable of carrying torsion moment. a)True b)- False

Taya2010 [7]

Answer:

True

Explanation:

An aircraft is subject to 3 primary rotations

1) About longitudinal axis known as rolling

2) About lateral axis known as known as pitching

3) About the vertical axis known as yawing

The rolling of the aircraft induces torsion in the body of the aircraft thus the fuselage structure should be capable of carrying torsion

8 0

2 years ago

True or false? Engineering degree programs and engineering technology degree programs have a different requirements

sergey [27]

That’s true brother

4 0

3 years ago

A saturated 1.5 ft3 clay sample has a natural water content of 25%, shrinkage limit (SL) of 12% and a specific gravity (GS) of 2

Svetllana [295]

$79 f t^{3}$ is the volume of the sample when the water content is 10%.

<u>Explanation:</u>

Given Data:

$V_{1}=100\ \mathrm{ft}^{3}$

First has a natural water content of 25% = $\frac{25}{100}$ = 0.25

Shrinkage limit, $w_{1}=12 \%=\frac{12}{100}=0.12$

$G_{s}=2.70$

We need to determine the volume of the sample when the water content is 10% (0.10). As we know,

$V \propto[1+e]$

$\frac{V_{2}}{V_{1}}=\frac{1+e_{2}}{1+e_{1}}$ ------> eq 1

$e_{1}=\frac{w_{1} \times G_{s}}{S_{r}}$

The above equation is at $S_{r}=1$ ,

$e_{1}=w_{1} \times G_{s}$

Applying the given values, we get

$e_{1}=0.25 \times 2.70=0.675$

Shrinkage limit is lowest water content

$e_{2}=w_{2} \times G_{s}$

Applying the given values, we get

$e_{2}=0.12 \times 2.70=0.324$

Applying the found values in eq 1, we get

$\frac{V_{2}}{100}=\frac{1+0.324}{1+0.675}=\frac{1.324}{1.675}=0.7904$

$V_{2}=0.7904 \times 100=79\ \mathrm{ft}^{3}$

7 0

3 years ago

When the Moon is in the position shown, how would the Moon look to an observer on the North Pole?

kirill115 [55]

Answer:

cant see the moon sorry dude

5 0

2 years ago

A glass tube is inserted into a flowing stream of water with one opening directed upstream and the other end vertical. If the wa

Furkat [3]

Answer:

$h=0.46m$

Explanation:

From the question we are told that:

Velocity of water $V=3m/s$

Height=?

Generally, the equation for Water Velocity is mathematically given by

$V=\sqrt{2gh}$

Therefore Height h is given as

$h=\frac{v}{2g}$

$h=\frac{3^2}{2*9.81}$

$h=0.46m$

5 0

3 years ago