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Sloan [31]
3 years ago
8

what element has the electron configuration of 1s22s22p63s23p64s23d104p65s24d105p66s24f 145d106p67s25f 146d8

Chemistry
1 answer:
LekaFEV [45]3 years ago
8 0
It is the darmstadtium element that has the electron configuration above and the atomic number of 110
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Answer:

71.1

Explanation:

1 mol Fe = 10.4 g/55.85 g/mol = 0.186

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then since Ag:Fe is 1:3, AgNo3 is the limiting reactant

So now

0.178 moles * 1/3 * 241.83 g/mol Fe(NO3)3 = 14.35 g Fe(NO3)3

Excess reactant: 0.178 moes AgNO3 * 1/3 = 0.059

0.186 - 0.059 = 0.127 moles Fe * 55.85 g/mol Fe = 7.1 g Fe excess

8 0
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Answer:

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Explanation:

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3 years ago
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