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3 years ago

What is the difference between chemical and physical change with respect

Chemistry

2 answers:

kozerog [31]3 years ago

5 0

Answer:

Physical changes are changes that do not alter the identity of a substance. Chemical changes are changes that occur when one substance is turned into another substance.

Explanation:

zzz [600]3 years ago

5 0

Physical done change the identity and chemical change changes the identity of that object

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One of the reagents below gives predominantly 1,2 addition (direct addition) while the other gives predominantly 1,4 addition (c

Hunter-Best [27]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is reagent B

The skeletal structure of major organic product A is shown on the third uploaded image

Explanation:

The mechanism of the reaction for A and B are shown on the second the second reaction and looking at this we can see that the reagent that predominately gives 1,2 addition is reagent B

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3 years ago

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Nitric acid decomposes in light to form nitrogen dioxide, water, and oxygen, according to the following chemical equation.

geniusboy [140]

Answer:

b. 0.22 L

Explanation:

Step 1: Write the balanced equation

4 HNO₃(l) ⇒ 4 NO₂(g) + 2 H₂O(l) + O₂(g)

Step 2: Calculate the moles corresponding to 2.5 g of HNO₃

The molar mass of HNO₃ is 63.01 g/mol.

2.5 g × 1 mol/63.01 g = 0.040 mol

Step 3: Calculate the moles of O₂ produced from 0.040 moles of HNO₃

The molar ratio of HNO₃ to O₂ is 4:1. The moles of O₂ produced are 1/4 × 0.040 mol = 0.010 mol.

Step 4: Calculate the volume corresponding to 0.010 moles of O₂

Assuming the reaction takes place at standard temperature and pressure, the volume of 1 mole of O₂ is 22.4 L.

0.010 mol × 22.4L/1 mol = 0.22 L

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3 years ago

How many moles of chlorine are in 100g Chlorine (CI^2)?

Anni [7]

Answer:

35.453 good luck with your work

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3 years ago

What is a contributor of global warming?

iogann1982 [59]

Carbon dioxide emissions from, well, whatever emits CO2 really.

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3 years ago

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Ethene is converted to ethane by the reaction flows into a catalytic reactor at 25.0 atm and 250.°C with a flow rate of 1050. L/

Sphinxa [80]

Answer : The percent yield of the reaction is, 76.34 %

Explanation : Given,

Pressure of $C_2H_4$ and $H_2$ = 25.0 atm

Temperature of $C_2H_4$ and $H_2$ = $250^oC=273+250=523K$

Volume of $C_2H_4$ = 1050 L per min

Volume of $H_2$ = 1550 L per min

R = gas constant = 0.0821 L.atm/mole.K

Molar mass of $C_2H_6$ = 30 g/mole

First we have to calculate the moles of $C_2H_4$ and $H_2$ by using ideal gas equation.

For $C_2H_4$ :

$PV=nRT\\\\n=\frac{PV}{RT}$

$n=\frac{PV}{RT}=\frac{(25atm)\times (1050L)}{(0.0821L.atm/mole.K)\times (523K)}$

$n=611.34moles$

For $H_2$ :

$PV=nRT\\\\n=\frac{PV}{RT}$

$n=\frac{PV}{RT}=\frac{(25atm)\times (1550L)}{(0.0821L.atm/mole.K)\times (523K)}$

$n=902.46moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$C_2H_4+H_2\rightarrow C_2H_6$

From the balanced reaction we conclude that

As, 1 mole of $C_2H_4$ react with 1 mole of $H_2$

So, 611.34 mole of $C_2H_4$ react with 611.34 mole of $H_2$

From this we conclude that, $H_2$ is an excess reagent because the given moles are greater than the required moles and $C_2H_4$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $C_2H_6$ .

As, 1 mole of $C_2H_4$ react to give 1 mole of $C_2H_6$

As, 611.34 mole of $C_2H_4$ react to give 611.34 mole of $C_2H_6$

Now we have to calculate the mass of $C_2H_6$ .

$\text{Mass of }C_2H_6=\text{Moles of }C_2H_6\times \text{Molar mass of }C_2H_6$

$\text{Mass of }C_2H_6=(611.34mole)\times (30g/mole)=18340.2g$

The theoretical yield of $C_2H_6$ = 18340.2 g

The actual yield of $C_2H_6$ = 14.0 kg = 14000 g (1 kg = 1000 g)

Now we have to calculate the percent yield of $C_2H_6$

$\%\text{ yield of }C_2H_6=\frac{\text{Actual yield of }C_2H_6}{\text{Theoretical yield of }C_2H_6}\times 100=\frac{14000g}{18340.2g}\times 100=76.34\%$

Therefore, the percent yield of the reaction is, 76.34 %

5 0

3 years ago