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3 years ago

What is the balanced net ionic equation including phases for K2SO4 and SrI2

Chemistry

1 answer:

Triss [41]3 years ago

3 0

Answer:

Sr 2+(aq) + SO42-(aq) → SrSO4(s)

Explanation:

Step 1: Write a properly balanced equation with states:

K2SO4(aq) + Srl2(aq) → 2KI(aq) + SrSO4(s)

Step 2: write the full ionic equation with states. Remember to keep molecules intact. Only states (aq) will dissociate, (s) will not dissociate . This means SrSO4 won't dissociate.

2K+(aq) + SO42-(aq) + Sr 2+(aq) + 2I-(aq) → 2K+(aq) + 2I-(aq) + SrSO4(s)

Step 3: Balanced net ionic equation

Sr 2+(aq) + SO42-(aq) → SrSO4(s)

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What is the best definition of the enthalpy change Hr

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Answer:

The flow of thermal energy in a system, at constant atmospheric pressure AND at thermodynamic standard temperature and pressure.

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2 years ago

What is the angle between the carbon-sulfur bonds in the carbon disulfide ( cs2 ) molecule?

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Answer:

180º

Explanation:

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3 years ago

Write Huckel's rule below and determine how many electrons are required to make an aromatic ring with n = 0, 1, and 2.

lisov135 [29]

Answer: The number of electrons for n = 0, 1 and 2 are 2, 6 and 10 respectively.

Explanation:

Huckel's rule is used to determine the aromaticity in a compound. The number of delocalized $\pi-$ electrons are calculated by using the equation:

$\text{Number of delocalized }\pi-\text{ electrons}=4n+2$

where,

n = 0 or any whole number

Calculating the value of electrons for n = 0

Putting values in above equation, we get:

$\text{Number of delocalized }\pi-\text{ electrons}=4(0)+2=2$

Calculating the value of electrons for n = 1

Putting values in above equation, we get:

$\text{Number of delocalized }\pi-\text{ electrons}=4(1)+2=6$

Calculating the value of electrons for n = 2

Putting values in above equation, we get:

$\text{Number of delocalized }\pi-\text{ electrons}=4(2)+2=10$

Hence, the number of electrons for n = 0, 1 and 2 are 2, 6 and 10 respectively.

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3 years ago

PLEASE HELP!!!

neonofarm [45]

Answer:

$Cl_2+2NaI\rightarrow I_2+2NaCl$

Explanation:

Hello there!

In this case, according to the described chemical reaction, Cl2 replaces iodine in NaI in order to produce I2 and NaCl:

$Cl_2+NaI\rightarrow I_2+NaCl$

It is possible to realize how chlorine replaces iodine in agreement with the single displacement reaction. Moreover, since chlorine and iodine atoms are not correctly balanced, we add a 2 in front of both NaI and NaCl in order to do so:

$Cl_2+2NaI\rightarrow I_2+2NaCl$

Best regards!

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2 years ago

Which of the following best describes where cellular respiration occurs?

Illusion [34]

Answer:

In every body cell

Explanation:

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3 years ago

Read 2 more answers