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Schach [20]
3 years ago
15

An astronaut on a strange new planet having no atmosphere finds that she can jump up to a maximum height of 27 m when her initia

l upward speed is 6.0 m/s. what is the magnitude of the acceleration due to gravity on the planet?
Physics
2 answers:
Ganezh [65]3 years ago
8 0

Answer:

g=0.66\ m/s^2

Explanation:

Given that,

Initial upward speed, u = 6 m/s

Maximum height of the astronaut, h = 27 m

Let g is the acceleration due to gravity on the planet. It can be calculated using the conservation of energy as :

mgh=\dfrac{1}{2}mu^2

h=\dfrac{u^2}{2g}

g=\dfrac{u^2}{2h}

g=\dfrac{(6)^2}{2\times 27}

g=0.66\ m/s^2

So, the magnitude of the acceleration due to gravity on the planet is 0.66\ m/s^2. Hence, this is the required solution.  

vekshin13 years ago
7 0
The magnitude is 4.5
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What is the function of eye lens of human eye​
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2 years ago
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You throw a 20-n rock vertically into the air from ground level. you observe that when it is a height 15.4 m above the ground, i
gayaneshka [121]

I believe there are two things which we asked to find here:

1. its speed just as it left the ground

2. find its maximum height

 

Solutions:

1. We use the formula:

ΔKE = - ΔPE

where KE is kinetic energy = ½ mv^2, and PE is potential energy = m g h, Δ = change

Therefore:

½ m (v2^2 – v1^2) = m g (h1 – h2)

at initial point, point 1: h1 = 0, v1 = ?

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½ (24.2^2 – v1^2) = 9.8 (0 – 15.4)

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So the rock was travelling at 29.8 m/s as it left the ground.

 

2. The maximum height (hmax) reached is calculated using the formula:

v1^2 = 2 g hmax

Rewriting in terms of hmax:

hmax = v1^2 / 2 g

hmax = (29.8)^2 / (2 * 9.8)

hmax = 45.3 m

Therefore the rock reached a maximum height of 45.3 meters.

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3 years ago
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