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Schach [20]
3 years ago
15

An astronaut on a strange new planet having no atmosphere finds that she can jump up to a maximum height of 27 m when her initia

l upward speed is 6.0 m/s. what is the magnitude of the acceleration due to gravity on the planet?
Physics
2 answers:
Ganezh [65]3 years ago
8 0

Answer:

g=0.66\ m/s^2

Explanation:

Given that,

Initial upward speed, u = 6 m/s

Maximum height of the astronaut, h = 27 m

Let g is the acceleration due to gravity on the planet. It can be calculated using the conservation of energy as :

mgh=\dfrac{1}{2}mu^2

h=\dfrac{u^2}{2g}

g=\dfrac{u^2}{2h}

g=\dfrac{(6)^2}{2\times 27}

g=0.66\ m/s^2

So, the magnitude of the acceleration due to gravity on the planet is 0.66\ m/s^2. Hence, this is the required solution.  

vekshin13 years ago
7 0
The magnitude is 4.5
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A robin flies a distance of 45963 cm. How far has it flown in kilometers?
alina1380 [7]

Answer:

0.46km

Explanation:

45963cm/100cm=459.63m/1000m=0.45963 or 0.46km

6 0
2 years ago
A rectangular sharp-crested weir is contracted on both sides, and the opening is 1.2 m wide. At what height (Hw) should it be pl
Alex

Answer:

H_w = 2.129 m

Explanation:

given,

Width of the weir, B = 1.2 m

Depth of the upstream weir, y = 2.5 m

Discharge, Q = 0.5 m³/s

Weir coefficient, C_w = 1.84 m

Now, calculating the water head over the weir

Q = C_w BH^{3/2}

H = (\dfrac{Q}{C_wB})^{2/3}

H = (\dfrac{0.5}{1.84\times 1.2})^{2/3}

H = 0.371\ m

now, level of weir on the channel

H_w = y - H

H_w = 2.5 - 0.371

H_w = 2.129 m

Height at which weir should place is equal to 2.129 m.

7 0
3 years ago
Which shared property belongs in the region marked "B"?
NNADVOKAT [17]
The properti that you didnt share
4 0
3 years ago
A lead ball has a mass of 55.0 grams and a density of 11.4 g/cm3. what is the volume of the ball?
lesantik [10]
Density=mass/volume therefore volume=mass/density; 55g/11.4g/cm^3= 4.82cm^3
6 0
2 years ago
Read 2 more answers
If a liquid has a density of 1.67 g/cm^3, what is the volume of 45g of the liquid?
Aloiza [94]

Answer:

V = 26.95 cm³

Explanation:

Density is given by the formula :

ρ = m÷V

Density = mass ÷ Volume

Given both density and mass we rearrange, substitute and solve for Volume :

Rearranging the equation to make Volume the subject :

ρ = m÷V

ρV = m

V = m÷ ρ

Now substitute :

V = 45 ÷ 1.67

V = 26.9461077844

Take 2 decimal places as the density is 2 decimal places :

V = 26.95

Units will be cm³ as it is volume

Hope this helped and have a good day

8 0
2 years ago
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