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Harlamova29_29 [7]
3 years ago
11

Which type of force is changing the object's speed and direction when a toy clown pops out of a jack-in-the-box?

Physics
2 answers:
pochemuha3 years ago
4 0

The correct answer is

B. push


To be more precise, the force that changes the speed and direction of the toy clown is the elastic force due to the spring: when the box is closed, the spring is compressed, so all the energy is stored in the elastic potential energy store of the spring. As the box opens, the spring is free to stretch, therefore it pushes the toy out of the box, transferring all the elastic potential energy into kinetic energy of motion of the toy clown.

Murrr4er [49]3 years ago
3 0
I think it would be d because the spring or whatever was pushing until it reached the farthest it could then it would pull down but idrk
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Por que el movimiento de un auto que recorre una pista circular ni es M.R.U.V​
tigry1 [53]

Answer:

Salta al contenido principal

Contenido principal

Movimiento rectilíneo uniforme (MRU)

Movimiento Rectilíneo

Movimiento rectilíneo uniforme (MRU)

Imagina que eres un astronauta en la Estación Espacial Internacional. Estás arreglando unos paneles solares averiados, cuando de pronto, al presionar, tu destornillador sale disparado de tus manos. Si no lo atrapas a tiempo, el destornillador estará viajando por el espacio en línea recta y a velocidad constante, a menos que algo se interponga en su camino. Esto sucede porque la herramienta se mueve con movimiento rectilíneo uniforme, o MRU.

Foto de la Estación Espacial Internacional

Foto de la Estación Espacial Internacional

Estación Epacial Internacional orbitando nuestro planeta. Créditos: International Space Station orbiting above earth de la National Reconnaissance Office.

El MRU se define el movimiento en el cual un objeto se desplaza en línea recta, en una sola dirección, recorriendo distancias iguales en el mismo intervalo de tiempo, manteniendo en todo su movimiento una velocidad constante y sin aceleración.

Recuerda que la velocidad es un vector, entonces, al ser constante, no varía ni su magnitud, ni su dirección de movimiento.

Condiciones del MRU

Para que un cuerpo esté en MRU, es necesario que se cumpla la siguiente relación:

t−t

0

x−x

0

Constante

Donde

xxx: es la posición en el espacio y

ttt: es el tiempo.

De esta condición, llegamos a la ecuación del MRU:

x = x_0 + v(t-t_0)x=x

0

+v(t−t

0

)x, equals, x, start subscript, 0, end subscript, plus, v, left parenthesis, t, minus, t, start subscript, 0, end subscript, right parenthesis

Donde:

\Large x_0x

0

x, start subscript, 0, end subscript: posición en el instante \Large t_0t

0

t, start subscript, 0, end subscript

\Large xxx: Posición en el instante \Large ttt

Esto quiere decir que si conocemos la posición x_0x

0

x, start subscript, 0, end subscript en el instante t_0t

0

t, start subscript, 0, end subscript y sabemos cuál es la de la velocidad vvv, podremos conocer la posición xxx en cualquier instante ttt.

¡No olvides fijarte bien en las unidades que utilizas y de convertirlas si es necesario!

Veamos un ejemplo:

Imagínate que has programado un carro robótico para que tenga una velocidad constante ¿Puedes calcular a qué distancia desde el punto de partida estará luego de 30\text{ s}30 s30, start text, space, s, end text?

Tienes los siguientes datos:

v

x

0

t

0

t

=10 m/s

=0 m

=0 s

=30 s

Explanation:

espero y esto te ayude

5 0
3 years ago
Sound waves travel through air at a speed of 330 m/s. A whistle blast at a frequency of about 1.0 kHz lasts for 2.0 s. (a) Over
klasskru [66]

Answer:

a)   x = 660 m , b)    λ = 0.330 m , c) precision  is 0.1 cm , d)    Δf= n Δt/ t²

Explanation:

a) the speed of sound is constant, therefore we can use the relation of motion to inform the distance that the sound extends is

        v = x / t

         x = v t

         x = 330 2

         x = 660 m

b) the speed of sound is

          v = λ f

          λ = v / f

          λ = 330/1000

          λ = 0.330 m

c) a measuring tape must be used to measure the wavelength, the precision  is 0.1 cm

.d) frequency measurement is more delicate, a stopwatch should be used to measure a certain number of oscillations, and hence calculate the frequency

         .f = n / t

Therefore, if we assume that there is no error in the number of oscillations, the pressure is given by the appreciation of the stopwatch, which is maximum 0.01 s

           Δf / f = Δt / t

           Δf = Δt /t   f

           Δf= n Δt/ t²

3 0
4 years ago
A cannonball with a mass of 50 kilograms and a golf ball with a mass of 0. 8 kilograms are dropped in a vacuum from a height of
Mnenie [13.5K]

It's gonna take a huge amount of time and effort, and we're gonna spend a huge amount of money, to build a vacuum chamber big enough to do this experiment.  

So when we're finally ready to try it, the cannonball and golf ball will make a  kind of cute experiment, but let's make it <em>really interesting</em>.  Let's ALSO try it with a feather, an apple, a watermelon, a tennis ball, a basketball, a coffeepot, a chair, an old computer, a set of dishes, a trombone, a bicycle, a math book, a TV set, a gallon of milk, a skateboard, a shotgun, a concrete block, a car, a waterbed, a schoolbus, a battleship, your dog, and my wife !

Drop every single one of them from a height of 10 meters.

<em>Every single one of them</em> accelerates at 9.8 m/s² as it falls, takes 1.429 seconds to reach the floor, and hits the floor at a speed of 14 m/s.  The feather, the schoolbus, and my wife stay <u><em>together</em></u> all the way down.

The only way this doesn't happen is if ...

-- you do this experiment in some other place that's not Earth, or

-- you throw one of the objects and you don't just drop it, or

-- the vacuum chamber has a leak and some air gets into it.

Because that's how gravity works.

4 0
4 years ago
Jared made a study chart about heat, temperature, kinetic energy, and thermal energy. A chart with 2 columns and 5 rows. The fir
Maurinko [17]

Answer:

Switch the term "heat" with the term "thermal energy."

Explanation:

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3 years ago
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