Question

The dimensions of aluminum foil in a box for sale in super markets are 66 2/3 yards by 12 inches. the mass of the foil is 0.83 kg. if its density is 2.70 g/cm3 , then what is the thickness of the foil in inches?

Answer 1

Length of the sheet is given as

$L = \frac{200}{3} yards = 6096 cm$

width of the sheet is given as

$w = 12 inches = 30.48 cm$

now let say its thickness is "t"

so the volume of the sheet is given as

$V = L*w*t$

$V = 6096*30.48* t$

$V = 185806.08*t cm^3$

mass of the sheet is given as

$m = 0.83 kg = 830 gram$

now we have

$density = \frac{mass}{volume}$

$2.70 = \frac{830}{185806.08*t}$

by solving above we have

$t = 1.65 * 10^{-3} cm$

so the thickness of sheet will be above