Answer:
A) 32.22 N/m b) 0.0156 m c) 4 Hz
Explanation:
Using Hooke's law;
T = 2π √m/k where m is mass of the body in kg and k is the force constant of the spring N/m and T is the period of vibration in s.
M = 51 g = 51 / 1000 in kg = 0.051kg
Make k subject of the formula
T/2π = √m / k
Square both sides
T^2 / 4π^2 = m/k
Cross multiply
K = 4 π^2 * m/T^2
K = 4 * 3.142 * 3.142 * 0.051/ 0.25^2= 32.22N/m
B) using Hooke's law;
F = k e where e is the maximum displacement of the spring from equilibrium point called amplitude
F= weight of the body = mass * acceleration due to gravity = 0.051*9.81
0.5 = 32.22 * e
e = 0.5/32.22 = 0.0156 m
C) frequency is the number of cycle completed in a second = 1 / period
F = 1 / 0.25 = 4Hz
If two parallel wires carry current in opposite directions, they repel each other whereas if two parallel wires carry current in same direction, they attract each other.
force of the wire2 will be more compared to that of wire1.
According to force formula, wire2 will generate more force compared to wire1
force=magnetic flux density × current × length
here,
current is directly proportional to the force, so with increase in current the force will also increase.
force depends on the length and current of the wire.
So, from this we can conclude that wire 2 will produce more force compared to wire 1.
To learn more about the force
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Answer:
he does no work on the wall coz wall didn't move
the wall doesn't move so the energy that he use will be wasted
the force that he put on the wall is also zero since the wall didn't move
Answer:
a) 
b) 
c) 
d) 
Explanation:
Given:
- mass of the astronaut,
- vertical displacement of the astronaut,
- acceleration of the astronaut while the lift,
a)
<u>Now the force of lift by the helicopter:</u>
Here the lift force is the resultant of the force of gravity being overcome by the force of helicopter.
where:
force by the helicopter
force of gravity
b)
The gravitational force on the astronaut:
d)
Since the astronaut has been picked from an ocean we assume her initial velocity to be zero, 
using equation of motion:
c)
Hence the kinetic energy:
Answer:
the terminal velocity v_t= 202.96 m/s≅203 m/s
Explanation:
The expression for the terminal velocity
here, C_d is the drag coefficient for the cylinder is 1.15
The surface density of the air at 20°C is
ρ_surface = 1.2041 kg/m^3
the density of air at an altitude of 39000 m
ρ= 4.3/100×39000 = 0.05177 kg/m^3
now substitute these values in equation above
we get
v_t= 202.96 m/s≅203 m/s
the terminal velocity v_t= 202.96 m/s≅203 m/s
