Question

What is the answer to the below questions 1.Find the sum of 72−104+5and -32+ 4-10. 2.What should be added to 32+32+3 to get 3+3? 3.Subtract the sum of 12ab –10bc –18ac and 9ab +12bc + 14ac from the sum of ab + 2bc and 3bc –ac

Answer 1

Answer:

-65

-61

20ab - 3bc - 3ac

Step-by-step explanation:

1.) Find the sum of 72−104+5and -32+ 4-10.

72 - 104 + 5 = - 27

- 32 + 4 - 10 = - 38

Sum of (-27 and - 38) = - 27 + (-38) = - 65

2.) What should be added to 32+32+3 to get 3+3

32 + 32 + 3 = 67

3 + 3 = 6

67 + x = 6

x = 6 - 67

x = - 61

3.) Subtract the sum of 12ab –10bc –18ac and 9ab +12bc + 14ac from the sum of ab + 2bc and 3bc –ac

(12ab –10bc –18ac) + (9ab +12bc + 14ac)

12ab + 9ab - 10bc + 12bc - 18ac + 14ac

= 21ab + 2bc - 4ac

(ab + 2bc) + (3bc - ac)

ab + 2bc + 3bc - ac

ab + 5bc - ac

(21ab + 2bc - 4ac) - (ab + 5bc - ac)

21ab + 2bc - 4ac - ab - 5bc + ac

21ab - ab + 2bc - 5bc - 4ac + ac

20ab - 3bc - 3ac