Question

A thin soap bubble of index of refraction 1.33 is viewed with light of wavelength 550.0nm and appears very bright. Predict a possible value of the thickness of the soap bubble.

Answer 1

Answer:

Thickness = 103.38 nm

Explanation:

Given that:

The refractive index of the thin soap bubble = 1.33

The wavelength of the light = 550 nm

The minimum thickness that produces a bright fringe can be calculated by using the formula shown below as:

$Thickness=\frac {\lambda}{4\times n}$

Where, n is the refractive index of the thin soap bubble = 1.33

${\lambda}$ is the wavelength

So, thickness is:

$Thickness=\frac {550\ nm}{4\times 1.33}$

Thickness = 103.38 nm