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kipiarov [429]
3 years ago
12

A thin soap bubble of index of refraction 1.33 is viewed with light of wavelength 550.0nm and appears very bright. Predict a pos

sible value of the thickness of the soap bubble.
Physics
1 answer:
Firlakuza [10]3 years ago
3 0

Answer:

Thickness = 103.38 nm

Explanation:

Given that:

The refractive index of the thin soap bubble = 1.33

The wavelength of the light = 550 nm

The minimum thickness that produces a bright fringe can be calculated by using the formula shown below as:

Thickness=\frac {\lambda}{4\times n}

Where, n is the refractive index of the thin soap bubble = 1.33

{\lambda} is the wavelength

So, thickness is:

Thickness=\frac {550\ nm}{4\times 1.33}

<u>Thickness = 103.38 nm</u>

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