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postnew [5]
3 years ago
5

what is the resistance of a clock if it has a current of 0.30 a and runs on a 9.0-v battery? 0.033 2.7 9.3 30

Physics
2 answers:
OleMash [197]3 years ago
6 0

Answer : Resistance of a clock is  30\ \Omega.

Explanation :

It is given that :

The current flowing in the clock, I = 0.3 A

Potential difference, V = 9 V

According to Ohm's law :

V=I\times R

So,

R=\dfrac{V}{I}

R=\dfrac{9\ V}{0.3\ A}

R=30\ \Omega

\Omega is the SI unit of the resistance given by a physicist Georg Simon Ohm.

So, the correct option is (d) i.e. 30\ \Omega

Hence, this is the required solution.

Nataliya [291]3 years ago
5 0
R = V/I =  9 / 0.3

R = 30 ohms.
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exis [7]

Answer:

The distance is 54.6 m

Explanation:

Given that,

Mass = 2.0 kg

Frictional coefficient = 0.21

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We need to calculate the acceleration

Using formula of frictional force  

F = \mu mg

F=0.21\times2.0\times9.8

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F = ma

a = \dfrac{F}{m}

a =\dfrac{4.12}{2.0}

a=2.06\ m/s^2

We need to calculate the initial velocity

Using equation of motion

v^2=u^2-2as

Put the value  

0=15^2-2\times2.06\times s

s = \dfrac{15^2}{2\times2.06}

s=54.6\ m

Hence, The distance will be 54.6 m.

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3 years ago
What is a dependent or responding variable? Can someone help me?
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They are a variable that changes as a result of the changes in the manipulated variable

8 0
3 years ago
An aluminum cup of 150 cm3 capacity is completely filled with glycerin at 23°C. How much glycerin will spill out of the cup if t
AVprozaik [17]

Answer:

1.19cm^3 of glycerine

Explanation:

Let Vo= 150cm^3 for both aluminum and glycerine, using expansion formula:

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Volume of glycerine = coefficient of volume expansion of glycerine * Vo* change in temperature - coefficient of volume expansion of Aluminum*Vo* change temperature

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Change in temperature = 41-23 = 18oC

Volume of glycerine that spill = (5.1*10^-4) - (0.69*10^-4) (150*18) = 4.41*10^-4*2700 = 1.19cm3

3 0
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A grandfather clock works by swinging a pendulum back and forth with a
allochka39001 [22]

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3 years ago
Someone please help with this
SSSSS [86.1K]

Answer:

<em>The new force is 2/3 of the original force</em>

Explanation:

<u>Coulomb's Law </u>

The electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Written as a formula:

\displaystyle F=k\frac{q_1q_2}{d^2}

Where:

k=9\cdot 10^9\ N.m^2/c^2

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d= The distance between the objects

Suppose the first charge is doubled (2q1) and the second charge is one-third of the original charge (q2/3). Now the force is:

\displaystyle F'=k\frac{2q_1*q_2/3}{d^2}

Factoring out 2/3:

\displaystyle F'=\frac{2}{3}k\frac{q_1*q_2}{d^2}

Substituting the original force:

F'=\frac{2}{3}F

The new force is 2/3 of the original force

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