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Alecsey [184]
3 years ago
5

Alpha Centauri B is a star that is about the same size as the Sun. Why does it appear much smaller and dimmer than the Sun when

seen from Earth?
Chemistry
2 answers:
Ugo [173]3 years ago
4 0
 To the eye – taken by itself – Alpha Centauri A appears as the fourth-brightest star seen from Earth, just slightly outshone by Arcturus. However, the combined light of Alpha Centauri A and B is slightly greater than Arcturus, so in that sense it appears as the third-brightest star visible in Earth's sky.
Nookie1986 [14]3 years ago
3 0

Answer:

Alpha Centauri B appears much smaller and dimmer than Sun, due to its greater distance from earth than Sun's and its lesser temperature than Sun, respectively.

Explanation:

Alpha Centauri B has a mass of 0.907 times the mass of Sun. But, its luminosity is less than that of the luminosity of Sun, because its temperature (5260 K) is less than that of the Sun (5778 K).

<u>This, is the reason why Alpha Centauri B appears dimmer than the Sun.</u>

The Sun is at a distance of 0.000015559 light years from earth, while Alpha Centauri B is at much larger distance of 4.37 light years from Earth.

<u>Due, to this reason Alpha Centaurus B appears much smaller than the Sun from Earth.</u>

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If 25.3 grams of mercury(II) oxide react to form 23.4 grams of mercury, how many grams of oxygen must simultaneously be formed?
sergij07 [2.7K]

Answer : The mass of oxygen formed must be 3.8 grams.

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

2HgO\rightarrow 2Hg+O_2

According to the law of conservation of mass,

Total mass of reactant side = Total mass of product side

Total mass of 2HgO = Total mass of 2Hg+O_2

As we are given :

The mass of HgO = 25.3 grams

The mass of Hg = 23.4 grams

So,

2\times 25.3g=2\times 23.4g+\text{Mass of }O_2

50.6g=46.8g+\text{Mass of }O_2

\text{Mass of }O_2=3.8g

Therefore, the mass of oxygen formed must be 3.8 grams.

6 0
3 years ago
Nitrogen monoxide and water react to form ammonia and oxygen, like this: (g)(g)(g)(g) Write the pressure equilibrium constant ex
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Answer:

Kp = \frac{P(NH_{3}) ^{4} P(O_{2}) ^{5}}{P(NO) ^{4} P(H_{2}O)^{6}}

Explanation:

First, we have to write the balanced chemical equation for the reaction. Nitrogen monoxide (NO) reacts with water (H₂O) to give ammonia (NH₃) and oxygen (O₂), according to the following:

NO(g) + H₂O(g) → NH₃(g) + O₂(g)

To balance the equation, we add the stoichiometric coefficients (4 for NH₃ and NO to balance N atoms, then 6 for H₂O to balance H atoms and then 5 for O₂ to balance O atoms):

4 NO(g) + 6 H₂O(g) → 4 NH₃(g) + 5 O₂(g)

All reactants and products are in the gaseous phase, so the equilibrium constant is expressed in terms of partial pressures (P) and is denoted as Kp. The Kp is expressed as the product of the reaction products (NH₃ and O₃) raised by their stoichiometric coefficients (4 and 5, respectively) divided into the product of the reaction reagents (NO and H₂O) raised by their stoichiometric coefficients (4 and 6, respectively). So, the pressure equilibrium constant expression is written as follows:

Kp = \frac{P(NH_{3}) ^{4} P(O_{2}) ^{5}}{P(NO) ^{4} P(H_{2}O)^{6}}

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