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2 years ago

13

11. Which of the following statements describe anions? Select all that apply.

1 answer:

Sveta_85 [38]2 years ago

4 0

The two first ones because it’s always the opposite

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Compare the appearance and pH of the unfiltered and filtered polluted water. What conclusion can be made based on these observat

Goryan [66]

Answer:

The unfiltered polluted water is not clear and is yellowish in color. The filtered polluted water is clear with a little bit of yellow color. The pH readings are beyond the range in which organisms can grow. Based on these observations, I can conclude that even though water may look clean, it could actually not be clean or it can still be harmful to living things.

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3 years ago

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How many moles is 130g of CoCl2

olya-2409 [2.1K]

Answer:

1 mol

Explanation:

The mass of CoCl2 is 129.83. 130 divided by the mass is 1. This is to convert the mass given to mols that exist in the sample.

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2 years ago

____Na + ____Cl2 ---> ____NaCl

IrinaVladis [17]

Here is the answer of the given question

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3 years ago

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The electrolysis of water forms H2 and O2. 2H2O 2H2 + O2 What is the percent yield of O2 if 10.2 g of O2 is produced from the de

BigorU [14]

<u>Answer:</u> The percent yield of oxygen gas is 67.53 %.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of water = 17.0 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

$\text{Moles of water}=\frac{17.0g}{18g/mol}=0.944mol$

For the given chemical equation:

$2H_2O\rightarrow 2H_2+O_2$

By Stoichiometry of the reaction:

2 moles of water produces 1 mole of oxygen gas

So, 0.944 moles of water will produce = $\frac{1}{2}\times 0.944=0.472moles$ of oxygen gas

Now, calculating the mass of oxygen gas from equation 1, we get:

Molar mass of oxygen gas = 32 g/mol

Moles of oxygen gas = 0.472 moles

Putting values in equation 1, we get:

$0.472mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.472mol\times 32g/mol)=15.104g$

To calculate the percentage yield of oxygen gas, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of oxygen gas = 10.2 g

Theoretical yield of oxygen gas = 15.104 g

Putting values in above equation, we get:

$\%\text{ yield of oxygen gas}=\frac{10.2g}{15.104g}\times 100\\\\\% \text{yield of oxygen gas}=67.53\%$

Hence, the percent yield of oxygen gas is 67.53 %.

7 0

3 years ago

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A compound is analyzed and found to contain selenium and bromine. When a specific sample is

ohaa [14]

Answer:

Empirical formula is SeBr₄

Explanation:

Given data:

Mass of selenium = 7.928 g

Mass of bromine = 32.072 g

Empirical formula = ?

Solution:

Number of gram atoms of Se = 7.928/ 78.96 = 0.1

Number of gram atoms of Br = 32.072 / 79.9 = 0.4

Atomic ratio:

Se : Br

0.1/0.1 : 0.4/0.1

1 : 4

Se : Br = 1 : 4

Empirical formula is SeBr₄

7 0

3 years ago