Bromine vs Chlorine | Br vs Cl
Halogens are group VII elements in the periodic table, and all are electronegative elements and have the capability to produce -1 anions.
Bromine
Bromine is denoted by the symbol Br. This is in the 4th period of the periodic table between chlorine and iodine halogens. Its electronic configuration is [Ar] 4s2 3d10 4p5. The atomic number of bromine is 35. Its atomic mass is 79.904. Bromine staChlorine is an element in the periodic table which is denoted by Cl. It is a halogen (17th group) in the 3rd period of the periodic table. The atomic number of chlorine is 17; thus, it has seventeen protons and seventeen electrons. Its electron configuration is written as 1s2 2s2 2p6 3s2 3p5. Since the p sub level should have 6 electrons to obtain the Argon, noble gas electron configuration, chlorine has the ability to attract an electron. ys as a red-brown color liquid at room temperature.
Answer:
A - NaCl is a product
D - Cl2 is a gas
Explanation:
Based on the chemical reaction;
2Na(s) + Cl2(g) → 2NaCl2
- Sodium metal reacts with chlorine gas to form sodium chloride. Sodium is in solid state, chlorine is in gaseous state and Sodium chloride is in solid state.
- In the chemical reaction, sodium and chlorine are reactants while sodium chloride is the product.
- Additionally the chemical reaction above is balanced so as to obey the law of conservation of mass.
it will produce aluminum hydride and lithium chloride.
Answer:
a)
b)
Explanation:
a) The reaction:
The free-energy expression:
![E=E_{red}-E_{ox]](https://tex.z-dn.net/?f=E%3DE_%7Bred%7D-E_%7Box%5D)
The element wich is reduced is the Fe and the one that oxidates is the Mg:
The electrons transfered (n) in this reaction are 2, so:
b) If you have values of enthalpy and enthropy you can calculate the free-energy by:
with T in Kelvin
Answer:
The new concentration will be 0.01 M.
Explanation:
To determine the new concentration we use the following formula.
concentration (1) × volume (1) = concentration (2) × volume (2)
concentration (1) = 0.1 M
volume (1) = 100 mL
concentration (2) = unknown
volume (2) = 100 mL + 900 mL = 1000 mL
concentration (2) = [concentration (1) × volume (1)] / volume (2)
concentration (2) = (0.1 × 100) / 1000 = 0.01 M
