A reaction is expected to produce 28.3 moles of hydrogen gas. If the hydrogen is collected at 297 K and 1.08 atm, what is the vo

Question

3 years ago

10

lume? 305 L H2 639 L H2 948 L H2 1,240 L H2

2 answers:

Scrat [10] · Answer 1 · 2022-04-26T12:38:06+03:00

Scrat [10]3 years ago

8 0

Answer:

639 L H2

Explanation:

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Vinil7 [7] · Answer 2 · 2022-04-26T10:54:14+03:00

Answer:

The correct answer is 639 L H₂

Explanation:

We use the ideal gas equation:

We have the following data:

n = 28.3 mol

T= 297 K

P= 1.08 atm

R= 0.082 L.atm/K.mol (gas constant)

We introduce the data in the gas equation to calculate the volume (V):

PV=nRT

⇒V =nRT/P = (28.3 mol x 0.082 L.atm/K.mol x 297 K)/(1.08 atm) = 638.2 L ≅ 639 L

Therefore, the correct option is 639 L H₂