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murzikaleks [220]
3 years ago
10

A reaction is expected to produce 28.3 moles of hydrogen gas. If the hydrogen is collected at 297 K and 1.08 atm, what is the vo

lume? 305 L H2 639 L H2 948 L H2 1,240 L H2
Chemistry
2 answers:
Scrat [10]3 years ago
8 0

Answer:

639 L H2

Explanation:

took the quiz

ur welcome

Vinil7 [7]3 years ago
4 0

Answer:

The correct answer is 639 L H₂

Explanation:

We use the ideal gas equation:

We have the following data:

n = 28.3 mol

T= 297 K

P= 1.08 atm

R= 0.082 L.atm/K.mol (gas constant)

We introduce the data in the gas equation to calculate the volume (V):

PV=nRT

⇒V =nRT/P = (28.3 mol x 0.082 L.atm/K.mol x 297 K)/(1.08 atm) = 638.2 L ≅ 639 L

Therefore, the correct option is  639 L H₂

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Write the nuclear equation to describe the alpha decay of 243 95 Am
motikmotik

Answer:

Here's what I get.

Explanation:

Your unbalanced nuclear equation is:

_{95}^{243}\text{Am} \longrightarrow \, _{x}^{y}\text{Z} +\, _{2}^{4}\text{He}

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.  

Then

  95 = x + 2, so x =   95 - 2 =    93

243 = y + 4, so y = 243 - 4 = 239

Element 93 is neptunium, so the nuclear equation becomes

_{95}^{243}\text{Am} \longrightarrow \, _{93}^{239}\text{Np} + \, _{2}^{4}\text{He}  

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