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3 years ago

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Chemistry

1 answer:

Anna [14]3 years ago

4 0

Answer:

Explanation:

1. HCl helps breakdown,absorb and digest food and also destroy bacterias in the stomach.

2. Organic Matter promotes good soil structure and act as reservoir of nutrients in the soil.

3. The nature of the solution is Basic

Reason... Blue litmus will remain blue in a basic solution and turn Red in an acidic solution

4. There's a number of test available for her to use but preferably... She should use the Litmus paper test. That's easier. An acidic solution will Turn a blue litmus red while the blue litmus will retain its blue color in a basic solution.

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PLEASE HELP ILL GIVE U BRAINLIEST What's something you learned about the periodic table

valina [46]

Answer:

The periodic table of elements puts all the known elements into groups with similar properties. This makes it an important tool for chemists, nanotechnologists, and other scientists. If you get to understand the periodic table and learn to use it, you'll be able to predict how chemicals will behave.

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Determine the limiting reactant when 30.0 g of propane, C3H8, is burned with 75.0 g of oxygen.

AnnZ [28]

Answer: The limiting reagent is oxygen gas.

Explanation:

Limiting reagent is defined as the reactant that is present in less amount and it limits the formation of products.

Excess reagent is defined as the reactant which is present in large amount.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For propane:

Given mass of propane = 30.0 g

Molar mass of propane = 44.1 g/mol

Putting values in equation 1, we get:

$\text{Moles of propane}=\frac{30.0g}{44.1g/mol}=0.680mol$

For oxygen:

Given mass of oxygen = 75.0 g

Molar mass of oxygen = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of propane}=\frac{75.0g}{32g/mol}=2.34mol$

The chemical equation for the combustion of propane follows:

$C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(l)$

By Stoichiometry of the reaction:

5 moles of oxygen gas reacts with 1 mole of propane.

So, 2.34 moles of oxygen gas will react with = $\frac{1}{5}\times 2.34=0.468mol$ of propane

As, given amount of propane is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen is considered as a limiting reagent because it limits the formation of product.

Hence, the limiting reagent is oxygen gas.

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What is the electron configuration of oxygen?

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Please help answer this Guy's​ HELP it's very Important​

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