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Airida [17]
3 years ago
15

A 5000 kg open train car is rolling on frictionless rails at 22 m/s when it starts pouring rain. A few minutes later, the car’s

speed is 20 m/s. What mass of water has collected in the car?
Physics
1 answer:
Phantasy [73]3 years ago
3 0

Answer:

500 kg

Explanation:

It is given that,

The mass of a open train car, M = 5000 kg

Speed of open train car, V = 22 m/s

A few minutes later, the car’s speed is 20 m/s

We need to find the mass of water collected in the car. It is based on the conservation of momentum as follows :

initial momentum = final momentum

Let m is final mass

MV=mv

m=\dfrac{MV}{v}\\\\m=\dfrac{5000\times 22}{20}\\\\=5500\ kg

Water collected = After mass of train - before mass of train

= 5500 - 5000

= 500 kg

So, 500 kg of water has collected in the car.

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An airplane with a mass of 5,000 kg needs to accelerate 5 m/s2 to take off before it reaches the end of the runway. How much for
Anastasy [175]

Answer:

<h2>25000 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 5000 × 5

We have the final answer as

<h3>25000 N</h3>

Hope this helps you

6 0
3 years ago
17. Suppose you were standing on a scale in an elevator in free fall. What would the scale read?
lianna [129]

17

What would the scale read? zero

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19 coasters accelerate down to simulate weight loss/zeroised. As do NASA planes,

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5 0
3 years ago
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A standing wave is created on a string of length 1.2 m. If the speed of the wave on the string is 60.0 m/s, what is the fundamen
coldgirl [10]

Answer:

Fundamental frequency in the string will be 25 Hz

Explanation:

We have given length of the string L = 1.2 m

Speed of the wave on the string v = 60 m/sec

We have to find the fundamental frequency

Fundamental frequency in the string is equal to f=\frac{v}{2L}, here v is velocity on the string and L is the length of the string

So frequency will be equal to f=\frac{v}{2L}=\frac{60}{2\times 1.2}=25Hz

So fundamental frequency will be 25 Hz

6 0
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lesya692 [45]
Mechanical energy equals the sum of potential and kinetic energy. During the process, all PE converts into KE, assuming air resistance is neglected. So, the mechanical energy does not change and is equal to the initial potential energy.
ME
=mgh
=0.005 x 9.81 x 3
=0.147J
6 0
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qaws [65]
B. secondary waves aka shear waves          
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