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Airida [17]
3 years ago
15

A 5000 kg open train car is rolling on frictionless rails at 22 m/s when it starts pouring rain. A few minutes later, the car’s

speed is 20 m/s. What mass of water has collected in the car?
Physics
1 answer:
Phantasy [73]3 years ago
3 0

Answer:

500 kg

Explanation:

It is given that,

The mass of a open train car, M = 5000 kg

Speed of open train car, V = 22 m/s

A few minutes later, the car’s speed is 20 m/s

We need to find the mass of water collected in the car. It is based on the conservation of momentum as follows :

initial momentum = final momentum

Let m is final mass

MV=mv

m=\dfrac{MV}{v}\\\\m=\dfrac{5000\times 22}{20}\\\\=5500\ kg

Water collected = After mass of train - before mass of train

= 5500 - 5000

= 500 kg

So, 500 kg of water has collected in the car.

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A 0.09-kg lead bullet traveling 182 m/s strikes an armor plate and comes to a stop. If all of the bullet's energy is converted t
Artemon [7]

Answer: Δθ = 127.4 K

Explanation: by using the law of conservation of energy, the kinetic energy of the bullet equals the heat energy on the plate.

Kinetic energy of bullet = mv²/2

Heat energy = mcΔθ

Where m = mass of bullet = 0.09kg, v = velocity of bullet = 182 m/s, c = specific heat capacity of lead bullet = 130 j/kgk

Δθ = change in temperature

mv²/2 = mcΔθ

With 'm' on both sides of the equation, they cancel out each other, hence we have that

v²/2 = cΔθ

v² = 2cΔθ

Δθ= v²/2c

Δθ = (182)²/2×130

Δθ = 33124/260

Δθ = 127.4 K

3 0
3 years ago
I have a problem in this questions?
photoshop1234 [79]

Answer:

8.46E+1

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = 39 C

Charge 2 (q₂) = –53 C

Force (F) of attraction = 26×10⁸ N

Electrical constant K) = 9×10⁹ Nm²/C²

Distance apart (r) =?

The distance between the two charges can be obtained as follow:

F = Kq₁q₂ / r²

26×10⁸ = 9×10⁹ × 39 × 53 / r²

26×10⁸ = 1.8603×10¹³ / r²

Cross multiply

26×10⁸ × r² = 1.8603×10¹³

Divide both side by 26×10⁸

r² = 1.8603×10¹³ / 26×10⁸

r² = 7155

Take the square root of both side

r = √7155

r = 84.6 m

r = 8.46E+1 m

7 0
2 years ago
. A chemistry student’s height is measured at 68.5 inches. How tall is the student in cm?
tatiyna

1 inch = 2.54 centimeters

All we need to do is multiply.

68.5 * 2.54 = 173.99cm

Best of Luck!

3 0
3 years ago
Read 2 more answers
Tech A says that a relay is a one-way electrical check valve used in alternators to change AC into DC. Tech B says that a relay
Setler [38]

Answer:

The correct answer is from Tech B.

Explanation:

The relay is an electromagnetic device, which is stimulated by a very weak electrical current to open or close a circuit.  It functions as a switch controlled by an electrical circuit in which, by means of a coil and an electromagnet, a sequence of one or several contactors is activated that allow to open or close other electrical circuits independent of the one that controls it.

Have a nice day!

7 0
3 years ago
A bike first accelerates from 0.0m/s to 4.5m/s in 4.5 s, the continues at this constant speed for another 6.0 s. What is the tot
Alex_Xolod [135]

Answer:

37.125 m

Explanation:

Using the equation of motion

s=ut+0.5at^{2} where s is distance, u is initial velocity, t is time and a is acceleration

<u>Distance during acceleration</u>

Acceleration, a=\frac {V_{final}-V_{initial}}{t} where V_{final} is final velocity and V_{initial} is initial velocity.

Substituting 0.0 m/s for initial velocity and 4.5 m/s for final velocity, acceleration will be

a=\frac {4.5 m/s-0 m/s}{4.5 s}=1 m/s^{2}

Then substituting u for 0 m/s, t for 4.5 s and a for 1 m/s^{2} into the equation of motion

s=0*4.5+ 0.5*1*4.5^{2}=0+10.125 =10.125 m

<u>Distance at a constant speed</u>

At a constant speed, there's no acceleration and since speed=distance/time then distance is speed*time

Distance=4.5 m/s*6 s=27 m

<u>Total distance</u>

Total=27+10.125=37.125 m

3 0
3 years ago
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