The formula to find yield is
(Actual Yield)/(Theorectical Yield) x100
Just do the math.
85.22% x 113 = 96.2986
Convert it to 3 significant figures
Ans: 96.3g
Answer:
a = 4
b = 3
Explanation:
<u>SOLUTION :-</u>
Balance it by using 'hit & trial' method , and you'll get the answer :-
2Fe₂O + 3C → <u>4</u>Fe + <u>3</u>CO₂
⇒ a = 4 ; b = 3
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<u>VERIFICATION :-</u>
<em>In reactant side of equation :-</em>
- Number of atoms in Fe = 2×2 = 4
- Number of atoms in O = 2×3 = 6
- Number of atoms in C = 3×1 = 3
<em>In product side of equation :-</em>
- Number of atoms in Fe = 4×1 = 4
- Number of atoms in C = 3×1 = 3
- Number of atoms in O = 3×2 = 6
Number of atoms of each element is equal in both reactant & product side of equation. Hence , the equation is balanced.
<u>Answer:</u> The mass of sucrose required is 69.08 g
<u>Explanation:</u>
To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

Or,

where,
= osmotic pressure of the solution = 8.80 atm
i = Van't hoff factor = 1 (for non-electrolytes)
Mass of solute (sucrose) = ?
Molar mass of sucrose = 342.3 g/mol
Volume of solution = 564 mL (Density of water = 1 g/mL)
R = Gas constant = 
T = Temperature of the solution = 290 K
Putting values in above equation, we get:

Hence, the mass of sucrose required is 69.08 g
Answer:
When chlorine (as a gas or dissolved in water) is added to sodium bromide solution, the chlorine takes the place of the bromine. Because chlorine is more reactive than bromine, it displaces bromine from sodium bromide. The solution turns brown. ... The chlorine has gone to form sodium chloride.