One hot day, you find yourself going to the refrigerator for a cold drink. In light of the concept of homeostasis, you're acting in terms of the drive-reduction theory.

7 0

3 years ago

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A mass of 5.00 kg pulls down vertically on a string that is wound around a rod of radius 0.100 m and negligible moment of inerti

Vladimir79 [104]

Answer:

The angular acceleration of the rod is 2 rad/s².

(a) is correct option.

Explanation:

Given that,

Mass of string = 5.00 kg

Radius = 0.100 m

Mass of disk = 125 kg

Radius of disk = 0.2 m

We need to calculate the acceleration

Using balance equation

$mg-T=ma$

Put the value of m

$5g-T=5a$ ....(I)

We need to calculate the tension

Using balance equation

$T\times r=I\times \alpha$

$T=\dfrac{I\times\alpha}{r}$

$T=\dfrac{\dfrac{mr^2}{2}\times\alpha}{r}$

$T=\dfrac{\dfrac{mr^2}{2}\times\dfrac{v}{r}}{r}$

Put the value into the formula

$T=\dfrac{\dfrac{125\times(0.2)^2}{2}\times a}{(0.1)^2}$

$T=250a$ ....(II)

From equation (I) and (II)

$255a=5g$

Put the value into the formula

$a=\dfrac{5\times9.8}{255}$

$a=0.2\ m/s^2$

We need to calculate the angular acceleration of the rod

Using formula of angular acceleration

$\alpha=\dfrac{a}{R}$

Put the value into the formula

$\alpha=\dfrac{0.2}{0.1}$

$\alpha=2\ rad/s^2$

Hence, The angular acceleration of the rod is 2 rad/s².

4 0

3 years ago

Help me answer this please

alexandr1967 [171]

density = mass / volume.

277/38 approx 280/40 approx 7

tin or zinc. use calculator

3 0

3 years ago