Answer:
The molar mass of water is 18 grams per mole. So in 18 grams of water, there are 6.02 x 1023 molecules.
One gallon of water is equal to 3.7854118 liters. If we assume that the water is at 4 °C (to keep things simple), the density of water is exactly 1 gram per milliliter, or 1 kilogram per liter. So 1 gallon of water at 4 °C weighs exactly 3.7854118 kilograms, or 3785.41118 grams.
If one mole of water weighs 18 grams, then there are 210.30 moles of water in a gallon. Since one mole of water is made up of 6.02 x 1023 molecules, in one gallon of water there are 1.266 x 1026 molecules.
That is: 126600000000000000000000000 molecules!
If we multiply that by the number of atoms in a single water molecule -- 3 atoms -- then we get:
379800000000000000000000000 atoms!
The RDA for iodine in adults is 150 micrograms
To meet this, one must consume:
150 / 0.7645
= 196.2 micrograms of potassium iodide per day.
E=hf is the answer gotta run now hope the best for yall
compress
or compressing gas
Answer:
V1= 0.305L
Explanation:
To find the initial volume of 1.25M potassium fluoride needed to make tge dilution specified in the question, we can use: C1 × V1 = C2 × V2
Since the question wants the volume in litres, convert 455 mL to L
455/ 1000
= 0.455 L
Now make the substitution
1.25 × V1 = 0.838 × 0.455
Rearrange to make V1 the subject
V1=
