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tester [92]
3 years ago
6

A high fountain of water is located at the center of a circular pool. Not wishing to get his feet wet, a student walks around th

e pool and measures its circumference to be 15m. Next, the student stands at the edge of the pool and uses a protractor to gauge the angle of elevation at the bottom of the fountain to be 55°. How high is the fountain?
Physics
1 answer:
Alisiya [41]3 years ago
8 0

Answer:

The fountain is 3.43 m high.

Explanation:

Circumference of the pool = 15 m.

C = 2\pir

where C is the circumference and r its radius.

r = \frac{C}{2\pi }

 = \frac{15}{2(\frac{22}{7}) }

r = 2.3864

radius of the pool = 2.40 m

So that the height of the fountain, h, can be determined by applying trigonometric function.

Tan θ = \frac{opposite}{adjacent}

Tan 55 = \frac{h}{2.4}

h = Tan 55 x 2.4

  = 1.4282 x 2.4

  = 3.4277

h = 3.43 m

The height of the fountain is 3.43 m.

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