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Step2247 [10]
3 years ago
12

1 point

Physics
1 answer:
iren [92.7K]3 years ago
4 0

Answer:

i need a girlfreind

Explanation:

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D. 1<br> 1.212.52<br> -2<br> 12<br> 12
harkovskaia [24]

Answer:

what?

Explanation:

7 0
3 years ago
The Skeleton does a surprising number of things. What are the three main Ones? lol, it's due today at 12:59 pm I need help.
ICE Princess25 [194]

Answer:

Support

Posture

Protection

Explanation:

Support – the skeleton keeps the body upright and provides a framework for muscle and tissue attachment.

Posture – the skeleton gives the correct shape to our body.

Protection – the bones of the skeleton protect the internal organs and reduce the risk of injury on impact.

5 0
3 years ago
Balance the following equations:
Alla [95]

Answer:

1)  \:  \:  \:   4Al+ 3MnO _{2}→ 3Mn + 2Al _{2} O _{3} \\ 2) \:  \:  \:2Ga + 3H _{2}SO _{4}  → Ga _{2} (SO _{4}) _{3}  +3 H _{2} \\ 3) \:  \:  \: Mg + 2HCI→ MgCl _{2}+ H _{2}

4 0
3 years ago
You see a total eclipse of the sun. Three Saros cycles later, you find yourself at the same location.
alukav5142 [94]

Answer:

The correct answer is B. You would not have to travel far to see another total eclipse  .

Explanation:

it is said that the way to predict or know beforehand if there is a lunar or solar eclipse is just to know the what is called the saros which are periods of exactly 223 synodic months and the eclipses are repeated or occurred in the same location every 3 Saros cycles.

5 0
3 years ago
A 0.305 kg book rests at an angle against one side of a bookshelf. The magnitude and direction of the total force exerted on the
tankabanditka [31]

Answer

given,

F_L= 1.52\ N

\theta_L= 31^0

mass of book = 0.305 Kg

so, from the diagram attached  below

F_L cos {\theta_L} + F_b sin {\theta_b} = m g

1.52 times cos {31^0} + F_b sin {\theta_b} = 0.305 \times 9.8

F_b sin {\theta_b} = 2.989 -1.303

F_b sin {\theta_b} = 1.686

computing horizontal component

F_b cos {\theta_b} = F_L sin {\theta_L}

cos {\theta_b} = \dfrac{F_L sin {\theta_L}}{F_b}

cos {\theta_b} = \dfrac{1.52 \times sin {31^0}}{1.686}

cos {\theta_b} = 0.464

θ = 62.35°

5 0
4 years ago
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