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labwork [276]
3 years ago
12

Different species of animals in a community would most likely be similar in O A. physical structure. O B. size. O c. abiotic req

uirements. O d. number of offspring produced. O E. genetic make-up.​
Chemistry
1 answer:
Komok [63]3 years ago
3 0
A physical structure
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Summarize the process of alcoholic fermentation in yeast
AysviL [449]

Alcoholic fermentation is mainly used by various yeast species to make energy.

If there is no oxygen available, the yeasts have in the alcoholic fermentation another possibility of energy supply. But they can - as compared with cellular respiration - recover substantially less energy from glucose, in the form of adenosine triphosphate (ATP): by complete oxidation, a molecule of glucose provides 36 molecules of ATP, but by alcoholic fermentation only 2 molecules of ATP. These two molecules are obtained in glycolysis, the first step in the chain of reactions for both cellular respiration and fermentation.

The two additional steps of the fermentation, and thus the production of ethanol serve not to make energy, but the regeneration of the NAD + cofactor used by the enzymes of glycolysis. As NAD + is available in limited quantities, it is converted by the NADH reduced state fermentation enzymes to the NAD + oxidized state by reduction of acetaldehyde to ethanol.

6 0
3 years ago
TIMED TEST PLS HELP (will give BRAINLIEST) According to some scientists, which is a cause of global warming? PICK ONLY ONE A) de
artcher [175]
I think its c maybe im not sure
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2 years ago
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How many moles of gas are in 4.4 mL at 1.2 atm?
kirza4 [7]
The Correct Answer Is 3.2
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2 years ago
Changes in which two characteristics can indicate a physical change?
liberstina [14]

Answer:

A-Shape

C-state

Explanation:

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A solution is made by combining 500 mL of 0.10 M HF (Ka=7.2 x 10^-4) with 300 mL of 0.15 M NaF. What is the pH of the resulting
n200080 [17]

Answer:

b) 3.10

Explanation:

HF ⇄ H + + F

Using Henderson-Hasselbalch Equation:

pH = pKa + log [A-]/[HA].

Where;

pKa = Dissociation constant = -log Ka

Hence, pKa of HF = -log 7.2 x 10^-4 = 3.14266

[A-] = concentration of conjugate base after dissociation = moles of base/total volume

          = 0.15 x 0.3/0.8

               = 0.05625 M

[HA] = concentration of the acid = moles of acid/total volume

             = 0.10 x 0.5/0.8

                    = 0.0625 M

Note: <em>Total volume = 500 + 300 = 800 mL = 0.8 dm3</em>

pH = 3.14266 + log [0.05625/0.0625]

      = 3.14267 + (-0.04575749056)

           = 3.09691250944

<em>From all the available options below:</em>

<em>a) 2.97 </em>

<em>b) 3.10 </em>

<em>c) 3.19 </em>

<em>d) 3.22 </em>

<em>e) 3.32</em>

The correct option is b.

4 0
3 years ago
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