Well, 2 litres is 2 kilograms. 1000 grams = 1 kilogram
So that means that 2 litres of water = 2000 grams
<u>Given:</u>
Moles of gas, n = 1.50 moles
Volume of cylinder, V = 15.0 L
Initial temperature, T1 = 100 C = (100 + 273)K = 373 K
Final temperature, T2 = 150 C = (150+273)K = 423 K
<u>To determine:</u>
The pressure ratio
<u>Explanation:</u>
Based on ideal gas law:
PV = nRT
P= pressure; V = volume; n = moles; R = gas constant and T = temperature
under constant n and V we have:
P/T = constant
(or) P1/P2 = T1/T2 ---------------Gay Lussac's law
where P1 and P2 are the initial and final pressures respectively
substituting for T1 and T2 we get:
P1/P2 = 373/423 = 0.882
Thus, the ratio of P2/P1 = 1.13
Ans: The pressure ratio is 1.13
Sorry I honestly have no idea I just want my points
A change will only occur one time in unidirectional.
Because
Cyclic : Cyclic compounds are chemical compounds having a basic non-linear structure. In other words, these are ring structures. One or more series of atoms in the compound is connected to form a ring structure.
Periodic : The periodic table of chemical elements, often called the periodic table, organizes all discovered chemical elements in rows (called periods) and columns (called groups) according to increasing atomic number.
Unidirectional : compound is operating or moving in one direction only and it does not move in other direction.
Bidirectional : Capable of reacting or functioning in two, usually opposite, directions.
Thus, A change will only occur one time in unidirectional.
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The given question is incomplete. The complete question is as follows.
A 2.300×10−2 m solution of nacl in water is at 20.0∘c. the sample was created by dissolving a sample of nacl in water and then bringing the volume up to 1.000 l. it was determined that the volume of water needed to do this was 999.4 ml . the density of water at 20.0∘c is 0.9982 g/ml.
Calculate the molality of the salt solution.
Express your answer to four significant figures and include the appropriate units.
Explanation:
Molality is defined as the number of moles present in kg of a solvent.
Mathematically, Molality = 
Also,
Mole of solute = Molarity of solute x Volume of solution
= (0.0230 M) x (1.000 L) = 0.0230 mol of solute
Therefore, mass of solvent will be as follows.
= 997.7 g
= 0.9977 kg (as 1 kg = 1000 g)
Therefore, we will calculate the molality as follows.
Molality = 
= 0.02306 mol/kg
thus, we can conclude that molality of the given solution is 0.02306 mol/kg.
