1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Veseljchak [2.6K]
3 years ago
15

If someone is building a scale model of our solar system which characteristic would be the most difficult to build into the mode

l?
1#The relative sizes of the objects
2#The colors of the objects
3#The distances between objects
4#The composition of the objects
Chemistry
1 answer:
nikitadnepr [17]3 years ago
5 0

Answer:

The composition of the objects because not all the planets have been explored

You might be interested in
What gas in the air is used by plants to make their own food? (2 points)
Varvara68 [4.7K]

Answer:

Carbon Dioxide

Explanation:

Carbon dioxide gets turned into oxygen

5 0
3 years ago
Read 2 more answers
Chemistry course is intended for what type of students?
yulyashka [42]

Answer:

Chemistry course is intended for students who did not take chemistry in high school or who struggled with high school chemistry.

Explanation:

4 0
3 years ago
A chemist must prepare 800ml of potassium hydroxide solution with a pH 13 of at 25. He will do this in three steps:
Naily [24]

Answer:

4.48 grams of potassium hydroxide that the chemist must be weighing out.

Explanation:

The pH of the KOH solution = 13

pH + pOH = 14

pOH = 14 - pH = 14 - 13 = 1

pOH=-\log[OH^-]

1=-\log[OH^-]

[OH^-]=0.1 M

KOH(aq)\rightarrow K^+(aq)+OH^-(aq)

1 mole of hydroxide ions are obtained from 1 mole of KOH. Then 0.1 mole of hydroxide ions will be obtained from :

\frac{1}{1}\times 0.1 M=0.1 M of KOH

[Molarity]=\frac{\text{Moles of solute}}{\text{Volume of solution(L)}}

Volume of KOH solution = 800 mL = 0.800 L ( 1 mL = 0.001 L)

0.1 M=\frac{\text{Moles of KOH}}{0.800 L}

Moles of KOH = 0.1 M × 0.800 L = 0.08 mol

Mass of 0.08 moles of KOH :

0.08 mol × 56 g/mol = 4.48 g

4.48 grams of potassium hydroxide that the chemist must be weighing out.

8 0
3 years ago
7. A solution containing 90grams of KNO3 per 100. grams of H2O at
Tomtit [17]

Answer:

(4) concentrated and supersaturated

Explanation:

At 50.°C, 90g of KNO3 lies above the solubility curve [on the Regents Reference Table G]. This indicates that the solution is supersaturated, meaning it contains more solute than will naturally dissolve, and was formed when a saturated solution cooled. Furthermore, the percent concentration of this solution is 90% KNO3 making this solution concentrated. This can be calculated using the formula for mass percent concentration.

Percent Mass = <u>Mass of Solute (g)</u> x 100

                         Mass of Solution (g)

5 0
3 years ago
Which of the following statements is untrue in regard to sound traveling in air? 
Karo-lina-s [1.5K]
I think the answer is B. 
5 0
3 years ago
Read 2 more answers
Other questions:
  • The first two steps in the industrial synthesis of nitric acid produce nitrogen dioxide from ammonia: 4 NH3(g) +502(g) = 4 NO(g)
    8·1 answer
  • The National Weather Service routinely supplies atmospheric pressure data to help pilots set their altimeters. The units the NWS
    6·1 answer
  • Describe the nucleus of an atom
    11·1 answer
  • A sheet of aluminum foil weighs 2.07g. If the sheet is 24cm long and 20cm wide, how thick is the sheet in micrometers? The densi
    10·1 answer
  • The principle of conservation of mass is satisfied in a chemical equation when
    11·1 answer
  • I need help with the question below:
    9·1 answer
  • The isotopes K-37 and K-42 have the same...
    6·1 answer
  • What element is on period 5 group/family 11
    10·1 answer
  • How many oxygen atoms are there in one molecule of CH3FO?
    7·1 answer
  • Maalox is the trade name for an antacid and antigas medication used for relief of heartburn, bloating, and acid indigestion. Eac
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!