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Veseljchak [2.6K]

2 years ago

15

If someone is building a scale model of our solar system which characteristic would be the most difficult to build into the mode

l?
1#The relative sizes of the objects
2#The colors of the objects
3#The distances between objects
4#The composition of the objects

1 answer:

nikitadnepr [17]2 years ago

5 0

Answer:

The composition of the objects because not all the planets have been explored

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There are eight markers in a full set, but Flora and Frank each only have seven markers. Flora is missing the red marker, and Fr

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Answer:

Put their markers together, now they have each color

Explanation:

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2 years ago

Read 2 more answers

Calculate the number of atoms in 0.25 moles of manganese?

White raven [17]

<h3>Answer:</h3>

1.5 × 10²³ atoms Mn

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<h3>Explanation:</h3>

<u>Step 1: Define</u>

0.25 mol Mn

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

Set up: $\displaystyle 0.25 \ mol \ Mn(\frac{6.022 \cdot 10^{23} \ atoms \ Mn}{1 \ mol \ Mn})$
Multiply: $\displaystyle 1.5055 \cdot 10^{23} \ atoms \ Mn$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

1.5055 × 10²³ atoms Mn ≈ 1.5 × 10²³ atoms Mn

3 0

2 years ago

What is the shape of a molecule that has 4 atoms bonded to a central atom

Nataliya [291]

Answer:

C. Tetrahedral

Explanation:

Tetrahedral would be the correct choice because the central atom has 4 domains (1 bond counts as 1 domain so 4 bonds =4) and no lone pairs which means it has tetra (which translates to four) domains hence tetrahedral.

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2 years ago

Which element in period 3 has both metallic and non metalik properties

Andrei [34K]

Answer:

Si is the answer I hope this help

6 0

2 years ago

In an experiment, a compound was determined to contain 68.94% oxygen and 31.06% of an unknown element by weight. The molecular w

monitta

Answer is: the compound is B₂O₃.

ω(O) = 68.94% ÷ 100%.

ω(O) = 0.6894; percentage of oxygen in the compound.

ω(X) = 31.06% ÷ 100%.

ω(X) = 0.3106; percentage of unknown element in the compound.

If we take 69.7 grams of the compound:

M(compound) = 69.7 g/mol.

n(compound) = 69.7 g ÷ 69.7 g/mol.

n(compound) = 1 mol.

n(O) = (69.7 g · 0.6894) ÷ 16 g/mol.

n(O) = 3 mol.

M(compound) = n(O) · M(O) + n(X) · M(X).

n(X) = 1 mol ⇒ M(X) = 21.7 g/mol; there is no element with this molecular weight.

n(X) = 2 mol ⇒ M(X) = 10.85 g/mol; this element is boron (B).

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2 years ago