Answer:
Resulting Change in the Magnetic Flux 
Explanation:
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The term you need to know is equilibrium. Technically it means that heat gained = heat lost. Normally in beginning chemistry classes the evidence for this condition is a stable temperature.
The electric potential energy of the charge is equal to the potential at the location of the charge, V, times the charge, q:

The potential is given by the magnitude of the electric field, E, times the distance, d:

So we have

(1)
However, the electric field is equal to the electrical force F divided by the charge q:

Therefore (1) becomes
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And if we use the data of the problem, we can calculate the electrical potential energy of the charge:
Total work done is 0.13 Joules
<h3>What is work done ?</h3>
The sum of the displacement and the component of the applied force of the object in the displacement direction is the work done by a force.
According to the given information
We need to find the work done
work done = force × distance
We are given,
force = 26 N
Distance = 0.0005 meter
hence ,
Work done = 26 × 0.005
= 0.13 Joules
Total work done is 0.13 Joules
To know more about Work done
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Answer:
2 m/s
Explanation:
From the conservation of momentum, the initial momentum of the system must be equal to the final momentum of the system.
Let the 10.00 kg mass be
and the 12.0 kg mass be
. When they collide and stick, they have a combined mass of
.
Momentum is given by
. Set up the following equation:
, where
is the desired final velocity of the masses.
Call the right direction positive. To indicate the 12.0 kg object is travelling left, its velocity should be substitute as -8.00 m/s.
Solving yields:
