4 years ago

What happens when an electron moves from an excited state to the ground state?

Physics

1 answer:

Darina [25.2K]4 years ago

6 0

When an electron moves from an excited state to the ground state, "Energy releases"

Hope this helps!

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Two foam peanuts become equally charged as they fall out of a cardboard box. Each foam peanut carries a charge of 8 x 10^-4 C. I

jok3333 [9.3K]

Answer:

Answer labeled B : 2,304,000 N

Explanation:

Recall the formula for the electric force:

$F_e=9\,\,10^9\, \, \frac{q_1*q_2}{d^2} \\F_e=9\,\,10^9\, \, \frac{8\,10^{-4}*8\,10^{-4}}{0.05^2} \\F_e=2,304,000\,\,N$

which agrees with answer B provided.

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3 years ago

Which statement describes the relationship between bond strength and the melting and boiling points of a substance?

kogti [31]

I think the answer will be B or C?

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3 years ago

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Gravity accelerates any object falling at 9.8 m/s2. What is the force that will be applied to the ground if an 88 kg box falls f

saw5 [17]

Answer:

The force is of the weight 862,4 Newtons.

Explanation:

We have the formula:

w = m * g

Data:

w = weight = ¿?

m = mass = 88 kg

g = gravity = 9,8 m/s

Replacing according formula:

w = 88 kg * 9,8 m/s

Resolving:

w = 862,4 N

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3 years ago

Describe the 3 types of projectiles.

Anna11 [10]

Answer:Although any object in motion through space (for example a thrown baseball, kicked football, fired bullet, thrown arrow, stone released from catapult) are projectiles, they are commonly found in warfare and sports.

Explanation:

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3 years ago

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the wattage ratting of a light bulb is the power it sonsumers when it is connected accross a 120 V potential difference what is

igor_vitrenko [27]

Answer:

240 Ω

Explanation:

Resistance: This can be defined as the opposition to the flow of current in an electric field. The S.I unit of resistance is ohms (Ω).

The expression for resistance power and voltage is give as,

P = V²/R.......................... Equation 1

Where P = Power, V = Voltage, R = Resistance

Making R the subject of the equation,

R = V²/P.................... Equation 2

Given: V = 120 V, P = 60 W.

Substitute into equation 2

R = 120²/60

R = 240 Ω

Hence the resistance of the bulb = 240 Ω

8 0

3 years ago