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Alik [6]
3 years ago
7

HELP WILL MARK BRAINLYESt

Mathematics
1 answer:
Tcecarenko [31]3 years ago
6 0

Answer:

i dont understand the problem, please explain to me what is going on?

Step-by-step explanation:

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Use the Pythagorean theorem to find the unknown side of the right triangle.
Nesterboy [21]

The length of hypotenuse is 39.

Step-by-step explanation:

Given,

Vertical side = a = 15

Horizontal side = b = 36

Hypotenuse = c

Using pythagorean theorem

a^2+b^2=c^2\\(15)^2+(36)^2=c^2\\225+1296=c^2\\1521=c^2\\c^2=1521

Taking square root on both sides

\sqrt{c^2}=\sqrt{1521}\\c=39

The length of hypotenuse is 39.

Keywords: square root, addition

Learn more about square roots at:

  • brainly.com/question/9196410
  • brainly.com/question/9178881

#LearnwithBrainly

8 0
3 years ago
For one month Siera calculated her home town’s average high temperature in degrees Fahrenheit. She wants to convert that tempera
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C(F) is the degrees Celsius given the degrees Fahrenheit.<span />
4 0
4 years ago
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The diagram above, not drawn to scale,shows a triangle, ABC, with area 28units². Show workings.
Valentin [98]

A. (0,-6)
plug in the area to the area formula for a triangle (A=1/2bh). so 28=1/2b(4) [since the height is 4]. divide by 4 (7=1/2b). multiply by 2/divide by 1/2 (14=b). the base equals 14 units long.
B. y=2/3x+4
find the slope of the line (2/3)
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4 0
3 years ago
Please help, I have so much work to do, and I have to fit in time to study for a huge test they will determine my future
worty [1.4K]

Answer:

11

13

15

23

Step-by-step explanation:

you substitute each x value in the table with the x in the equation

f(x)= 2x+13

f(x)= 2(-1)+13 .... repeat for each

6 0
3 years ago
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Two congruent 30-60-90 triangles are placed,as shown,so that they overlap partly and their hypotenuses coincide. If the hypotenu
Ede4ka [16]

Answer: The area common to both triangle is 31.77 sq. cm.

Step-by-step explanation:

Since we have given that

30-60-90 triangles are placed.

So, the ratio of sides would be

1:\sqrt{3}:2

Since Hypotenuse = 12 cm

So, it becomes,

2x=12\\\\x=\dfrac{12}{2}=6

So, Base would be

x=6\ cm

and Perpendicular would be

\sqrt{3}x=6\sqrt{3}

So, Area common to the both triangles would be

\dfrac{1}{2}\times base\times height\\\\=\dfrac{1}{2}\times 6\times 6\sqrt{3}\\\\=18\sqrt{3}\\\\=31.177

Hence, the area common to both triangle is 31.77 sq. cm.

4 0
3 years ago
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