Answer:
0.3354 m/s
Explanation:
Using the general equation of a wave,
x(t) = Acos(ωt+Φ)....................... Equation 1
Where x(t) = distance of the wave at an instantaneous time t, A = maximum displacement of the wave, ω = angular velocity, t = time, Φ = phase angle.
Note: v(t) = x(t)/t, and this is the differentiation of x(t)
V(t) = -Aω sin(ωt+Φ)............. Equation 2
From the equation above,
V(max) = Aω............... Equation 3
But,
ω = √(k/m)................ Equation 4
Where k = force constant of the spring, m = mass of the object.
Given: k = 1.25 N/m, m = 0.01 kg
Substitute these values into equation 4.
ω = √(1.25/0.01)
ω = √125
ω = 11.18 rad/s
Also given: A = 3.00 cm = 0.03 m
Substitute into equation 3
V(max) = 11.18(0.03)
V(max) = 0.3354 m/s
