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marissa [1.9K]
2 years ago
8

Assuming a current is flowing, what increases the strength of the magnetic field of a coiled electrical wire? Select all that ap

ply. Straightening the wire changing the direction of the current flow adding more coils to the wire placing a metal bar within the coils stopping the current.
Physics
1 answer:
goblinko [34]2 years ago
8 0

The strength of the magnetic field is increased by adding more coils to the wire and placing a metal bar within the coils.

The given problem is based on the concept and fundamentals of the magnetic strength in a current-carrying coil of wire. The current-carrying wire in a coiled form is known as Solenoid.

And the mathematical expression for the magnetic field in a solenoid is,[B = \dfrac{\mu_{0} \times N \times i}{L}

Here,

B is the strength of the magnetic field.

\mu_{0} is the magnetic permeability of free space.

N is the number of coils.

The strength of the magnetic field will increase by increasing the number of coils and placing the metallic slab (it will increase magnetic permeability) within the coils.

Thus, we can conclude that the strength of the magnetic field is increased by adding more coils to the wire and placing a metal bar within the coils.

learn more about the magnetic field here:

brainly.com/question/19542022

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3 years ago
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Answer:

There's one or two reasons, depending on what is meant by "wind-powered car".

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4 0
3 years ago
While driving north at 25 m/s during a rainstorm you notice that the rain makes an angle of 38° with the vertical. While driving
Natali [406]

Answer:21.33^{\circ}

Explanation:

Given

velocity of driver v_1=25 m/s w.r.t ground towards north

driver observes that rain is making an angle of 38^{\circ} with vertical

While returning v_2=25 m/s w.r.t. ground towards south

suppose u_1=velocity of rain drop relative car while car is going towards north

u_2=velocity of rain drop relative car while car is going towards south

z=vector sum of u_1 & v_1

Now from graph

\tan 38=\frac{v_1+v_2}{u_2}

u_2=\frac{25+25}{\tan 38}=64 m/s

z=\vec{u_2}+\vec{v_2}

therefore magnitude of z is given by

|z|=\sqrt{u_2^2+v_2^2}

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\tan A=\frac{v_2}{u_2}

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A=21.33^{\circ}

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6 0
3 years ago
A 49 N coconut is in a 15 m tree. What is te potential energy of the coconut?
eduard

Answer:

735 J

Explanation:

From the question given above, the following data were obtained:

Weight (W) = 49 N

Height (h) = 15 m

Potential energy =?

Potential energy is simply defined as the product of weight of the object and height to which the object is raised. Mathematically, it is expressed as:

Potential energy = weight × height

With the above formula, we can obtain the potential energy of the coconut as follow:

Weight (W) = 49 N

Height (h) = 15 m

Potential energy =?

Potential energy = weight × height

Potential energy = 49 × 15

Potential energy = 735 J

Thus, the potential energy of the coconut is 735 J

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