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3 years ago

Anya’s team won 5 out of every 7 games this season.

Mathematics

2 answers:

scoundrel [369]3 years ago

4 0

Answer:

20 wins

Step-by-step explanation:

28/7=4

4 times 5 =20

Colt1911 [192]3 years ago

3 0

Answer:

They won 15 games

Step-by-step explanation:

I am smart

Mark ME BRAINLIEST PLEASE

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Consider the next 1000 90% CIs for μ that a statistical consultant will obtain for various clients. Suppose the data sets on whi

Ivenika [448]

Answer:

90% CI expects to capture u 90% of time

(a) This means 0.9 * 1000 = 900 intervals will capture u

(b) Here we treat CI as binomial random variable, having probability 0.9 for success

n = 1000

p = 0.9

For this case, applying normal approximation to binomial, we get:

mean = n*p= 900

variance = n*p*(1-p) = 90

std dev = 9.4868

We want to Find : P(890 <= X <= 910) = P( 889.5 < X < 910.5) (integer continuity correction)

We convert to standard normal form, Z ~ N(0,1) by z1 = (x1 - u )/s

so z1 = (889.5 - 900 )/9.4868 = -1.11

so z2 = (910.5 - 900 )/9.4868 = 1.11

P( 889.5 < X < 910.5) = P(z1 < Z < z2) = P( Z < 1.11) - P(Z < -1.11)

= 0.8665 - 0.1335

= 0.733

6 0

3 years ago

Tell whether each integer is prime, composite or neither

melamori03 [73]

1.; 3.; 5. are prime numbers.
All others are composite numbers.
Good luck!

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3 years ago

A company has to buy computers and printers. Each computer, x, costs $595 and each printer, y, costs

fenix001 [56]

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3 years ago

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Write an equation of the graph: <br><br> y = |x| translated one unit to the right.

Bess [88]

Answer:

y= x-1

Step-by-step explanation:

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3 years ago

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According to the South Dakota Department of Health, the number of hours of TV viewing per week is higher among adult women than

nignag [31]

Answer: a) 73.84%, b) 77.64%.

Step-by-step explanation:

Since we have given that

Average number of hours women spent per week watching TV = 40

Standard deviation =4.7 hours

Average number of hours men spent per week watching TV = 34

Standard deviation = 5.2 hours

a. What percent of the women watch TV less than 43 hours per week? (Round z-score computation to 2 decimal places and your final answer to 4 decimal places.)

So, X is less than 43 hours.

So, we get that

$P(X$

b. ) What percent of the men watch TV more than 30 hours per week? (Round z-score computation to 2 decimal places and your final answer to 4 decimal places.)

Since Y is more than 30 hours per week

So, it becomes

$P(Y>30)=P(Z>\dfrac{30-34}{5.2})=P(Z>-0.77)\\\\=0.5+P(0$

Hence, a) 73.84%, b) 77.64%.

5 0

3 years ago