The correct answer is 1.2 m/s
: mv+mv=mv+mv
(0.5kg)(2m/s)+(0.4kg)(0m/s)=(0.5kg)v+(0.4kg)(1m/s)
= 1kg*m/s=(0.5kg)v+0.4kg*m/s
=1kg*m/s-0.4kg*m/s=(0.5kg)v
=0.6kg*m/s=(0.5kg)v
to solve for v we divide both side by 0.5kg
v=1.2m/s
Answer:
The kinetic energy of the bullet is 5.4 × 10³ J
Explanation:
Hi there!
The equation of kinetic energy is the following:
KE = 1/2 · m · v²
Where:
KE = kinetic energy.
m = mass of the bullet.
v = speed of the bullet.
Let´s convert the mass unit to kg so that our result is in Joules:
64 g · ( 1 kg / 1000 g) = 0.064 kg
Then, the kinetic energy will be the following:
KE = 1/2 · 0.064 kg · (411 m/s)²
KE = 5.4 × 10³ J
Answer:
499.523. meter
<em>I</em><em> hope</em><em> it's</em><em> helps</em><em> you</em>
Answer:
Option B
Explanation:
Looking at the 3 galvanometer readings given above, for galvanometer A, the reading is -2 mA.
For galvanometer B, the reading is 4 mA.
While for galvanometer C, the reading is -5 MA
Thus, option B is correct.
