First, let's calculate the total mechanical energy when the block is at rest and the spring is compressed 5 cm:

Now, let's use this total energy to calculate the velocity when the spring is compressed by 2.5 cm:

Therefore the speed is 1.026 m/s.
The equilibrium temperature of aluminium and water is 33.2°C
We know that specific heat of aluminium is 0.9 J/gm-K, and that of water is 1 J/gm-K
Now we can calculate the equilibrium temperature
(mc∆T)_aluminium=(mc∆T)_water
15.7*0.9*(53.2-T)=32.5*1*(T-24.5)
T=33.2°C
Answer:
h = 36.4 cm
Explanation:
given,
spring constant = 2.5 x 10⁴ N/m
compressed distance = 11.2 cm = 0.112 m
mass of the child = 44 kg
maximum height = ?
by energy of conservation






h = 0.364 m
h = 36.4 cm
Answer:
1) ironing a shirt 2) writing on surfaces 3) working of an eraser