1) rewrite the equation by completing the square
(X+4)^2=9
2) what are the solution to the equation
Answer A= X=-4 plus and minus 3
Answer:
![6\sqrt{5}](https://tex.z-dn.net/?f=6%5Csqrt%7B5%7D)
Step-by-step explanation:
In any right triangle, the Pythagorean theorem states:
, where
and
are two legs of the triangle and
is the hypotenuse.
Plugging in given values, we have:
![12^2+VU^2=18^2,\\144+VU^2=324,\\VU^2=180,VU=\sqrt{180}=\sqrt{36}\cdot \sqrt{5}=\boxed{6\sqrt{5}}](https://tex.z-dn.net/?f=12%5E2%2BVU%5E2%3D18%5E2%2C%5C%5C144%2BVU%5E2%3D324%2C%5C%5CVU%5E2%3D180%2CVU%3D%5Csqrt%7B180%7D%3D%5Csqrt%7B36%7D%5Ccdot%20%5Csqrt%7B5%7D%3D%5Cboxed%7B6%5Csqrt%7B5%7D%7D)
Given that the point B is (1,1) is rotate 90° counterclockwise around the origin.
We need to determine the coordinates of the resulting point B'.
<u>Coordinates of the point B':</u>
The general rule to rotate the point 90° counterclockwise around the origin is given by
![(x, y) \rightarrow(-y, x)](https://tex.z-dn.net/?f=%28x%2C%20y%29%20%5Crightarrow%28-y%2C%20x%29)
The new coordinate can be determined by interchanging the coordinates of x and y and changing the sign of y.
Now, we shall determine the coordinates of the point B' by substituting (1,1) in the general rule.
Thus, we have;
Coordinates of B' = ![(1,1) \rightarrow(-1,1)](https://tex.z-dn.net/?f=%281%2C1%29%20%5Crightarrow%28-1%2C1%29)
Thus, the coordinates of the resulting point B' is (-1,1)
24 divided by 3 = 8
but thers two third so 8+8=16
shen has saved $16.00
Hope this helps!