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Anni [7]
4 years ago
11

A passenger jet flies from one airport to another 1293 miles away in 2.1hours . Find average speed

Physics
1 answer:
JulsSmile [24]4 years ago
6 0

The average speed is 615.7 mph (275.2 m/s)

Explanation:

The average speed of an object gives a measure of how fast an object is moving over a certain time interval. It is a scalar quantity, and it is calculated as follows

v=\frac{d}{t}

where

v is the average speed

d is the distance covered

t is the time interval

For the jet in this problem, we have:

d = 1293 mi is the distance covered

t = 2.1 h is the time interval

Therefore, the average  speed is:

v=\frac{1293}{2.1}=615.7 mph

We can also convert into SI units (m/s), keeping in mind that:

1 mi = 1609 m\\1 h = 3600 s

And so

v=615.7 \frac{mi}{h}\cdot \frac{1609 m/mi}{3600 s/h}=275.2 m/s

Learn more about average speed:

brainly.com/question/8893949

brainly.com/question/5063905

#LearnwithBrainly

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As an admirer of Thomas Young, you perform a double-slit experiment in his honor. You set your slits 1.15 mm apart and position
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Answer:

The distance of the first bright fringe is given as  Y_C = 1.22 *10^{-3}m

The distance of the second dark fringe from the central bright fringe is given as  Y_D = 0.00192 \ m

Explanation:

From the question we are told that

     The slit separation distance is  d = 1.15 mm = \frac{1.15}{1000} =0.00115 m

      The distance of the slit from the screen is  D = 3.23 m

        The wavelength is \lambda  = 633 nm

For constructive interference to occur the distance between the two slit is mathematically represented as

            Y_C  =\frac{m \lambda D}{d}

 Where m is the order of the fringe which has a value of 1 for first bright fringe

    Substituting  values

               Y_C = \frac{1 * 633 *0^{-9} * 3.23}{0.00115}

                Y_C = 1.22 *10^{-3}m

For destructive  interference to occur the distance between the two slit is mathematically represented as

            Y_D  =  [n + \frac{1}{2} ] \frac{\lambda D}{d}

      m = 2

so the formula to get the dark fringe is n = \frac{1}{2} * 1

                                                                 n=1

 Now substituting values

                 Y_D = [ 1 + \frac{1}{2} ] * \frac{633 *10^{-9} * 3.23 }{0.00115}

                   Y_D =1.5 * \frac{633 *10^{-9} * 3.23 }{0.00115}

                        Y_D = 0.00192 \ m

4 0
3 years ago
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Answer:

This equation is based on twin paradox - a phenomena where one of the twin travels to space at a speed close to speed of light and the other remains on earth. the twin from the space on return discovers that the one on earth age faster.

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t_{o} = 10 years

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The problem can be solved by time dilation equation:

t = \frac{t_{o}}{\sqrt{1 - \frac{v^{2}}{c^{2}}}}            (1)

where,

t = time observed from a different inertial frame

Now, using eqn (1), we get:

t = \frac{10}{\sqrt{1 - \frac{(0.8c)^{2}}{c^{2}}}}

t = 16.67 years

The age of the twin on spaceship according to the one on earth = 25+16.67 =41.66 years

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bekas [8.4K]

Answer:

d. 50 C

Explanation:

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According to the 2nd law of thermodynamics, heat transfers from hot to cold temperature.

The quantity of both the different waters is equal so this makes it very easy. All we have to do is find the mean of both the temperatures:

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