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2 years ago

X^2/3 •5x =5x^5/3 Can someone explain how the exponent is 5/3?

1 answer:

8 0

Written an alternate way it is x^2/3 • 5x^3/3 (because 5x is to the power of one and in order to add fractions, you have to have the same denominator). So when you multiply the like terms, you add the exponents (2/3 and 3/3).

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Given cosθ=3√3 and sinθ<0 . What is the value of sinθ ?

guapka [62]

Answer:

Doesn't make sense.

Step-by-step explanation:

-1 ≤ cosθ ≤ 1

=> cosθ = 3√3 doesn't make sense.

7 0

2 years ago

What does a standard deviation of 0 indicates ?

DIA [1.3K]

What does a standard deviation of 0 indicates 0.

4 0

2 years ago

There has been much media coverage of the high cost of medicinal drugs in the United States. One concern is the large variation

umka21 [38]

Data for the question :

102.05 99.85 112.3 97.15 111.23 105.37 105.64 106.5 102.97 107.82 106.36 111.24 107.28 114.14 106.28 106.96 98.25 111.55 107.75 101.02 101.12 97.7 97.66 100.54 115.77 112.91 111.04 112.15 102.87 101.14 107.13 108.56 109.56 103.57 108.68 104.59 116.74 116.22 100.22 103.97 111.2 109.34 115.78 101.59 107.93 104.23 96.25 103.84 102.47 102.96 99.26 101.42 108.58 107.69 99.88 102.71 111.25 99.4 117.04 106.35 110.44 102.34 107.25 107.63 105.2 109.14 115.54 101.51 108.49 112.32 109.27 97.54 102.46 105.94 109.42 111.05 102.63 106.99 102.03 108.84 118.8 108.64 95.35 105.47 104.45 102.15 111.4 108.27 104.82 108.4 109.05 116.11 103.7 121.2 99.62 102.81 109.56 103.35 113.02 103.79

Answer:

Range = 25.35

Variance = 29.46

Standard deviation = 5.43

The variation in price of Prozac is high

Step-by-step explanation:

The range of the data :

Maximum - Minimum.

121.2 - 95.35 = 25.35

The variance, s :

s² = Σ(X - m²) / n - 1

Mean, m = Σx / n

X = individual data point

m = mean of data

n = sample size

Using a calculator of save time and ensure accuracy :

s² = 29.45522

The standard deviation, s

s = sqrt(variance)

s = sqrt(s²)

s = sqrt(29.45522)

s = 5.42726.

The range, variance and standard deviation, all measure the degree of variation in a dataset. The values of these statistical measure obtain for the price of 1 product across different pharmaceutical stores, suggests thatvthe variation in price is high;

With a range of about 25.35 and standard deviation of 5.43

4 0

2 years ago

Please help me with this problem, please

Harman [31]

Answer:

sin(x) = 5/13

cos(y) = 5/12

Therefore, sin(x) = cos(y)

Step-by-step explanation:

Trig ratios:

$sin(\theta)=\dfrac{O}{H}\\\\\\cos(\theta)=\dfrac{A}{H}\\\\\\tan(\theta)=\dfrac{O}{A}$

where $\theta$ is the angle, O is the measure of the side opposite the angle, A is the measure of the side adjacent to the angle and H is the hypotenuse, of a right triangle

We have been given the measures of the two legs, so we can find the measure of the hypotenuse by using Pythagoras' Theorem $a^2+b^2=c^2$

(where a and b are the legs and c is the hypotenuse of a right triangle)

$\implies 5^2+12^2=c"\\\\\implies 169=c^2\\\\\implies c=\sqrt{169}\\\\ \implies c=13$

Now we can use the trig ratios:

$\implies sin(x)=\dfrac{5}{13}$

$\implies cos(y)=\dfrac{5}{13}$

Therefore, sin(x) = cos(y)

8 0

2 years ago

Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation:

Vikentia [17]

Answer:

$\= x = 18.5$ , $\sigma = 5.15$

$15.505 < \mu < 21.495$

$14.93 < \mu < 22.069$

Step-by-step explanation:

From the question we are are told that

The sample data is 21, 14, 13, 24, 17, 22, 25, 12

The sample size is n = 8

Generally the ample mean is evaluated as

$\= x = \frac{\sum x }{n}$

$\= x = \frac{ 21 + 14 + 13 + 24 + 17 + 22+ 25 + 12 }{8}$

$\= x = 18.5$

Generally the standard deviation is mathematically evaluated as

$\sigma = \sqrt{\frac{\sum (x- \=x )^2}{n}}$

$\sigma = \sqrt{\frac{\sum ((21 - 18.5)^2 + (14-18.5)^2+ (13-18.5)^2+ (24-18.5)^2+ (17-18.5)^2+ (22-18.5)^2+ (25-18.5)^2+ (12 -18.5)^2 )}{8}}$

$\sigma = 5.15$

considering part b

Given that the confidence level is 90% then the significance level is evaluated as

$\alpha = 100-90$

$\alpha = 10\%$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table the value is

$Z_{\frac{ \alpha }{2} } = 1.645$

The margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E =1.645 * \frac{5.15 }{\sqrt{8} }$

=> $E = 2.995$

The 90% confidence interval is evaluated as

$\= x - E < \mu < \= x + E$

substituting values

$18.5 - 2.995 < \mu < 18.5 + 2.995$

$15.505 < \mu < 21.495$

considering part c

Given that the confidence level is 95% then the significance level is evaluated as

$\alpha = 100-95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table the value is

$Z_{\frac{ \alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E =1.96 * \frac{5.15 }{\sqrt{8} }$

=> $E = 3.569$

The 95% confidence interval is evaluated as

$\= x - E < \mu < \= x + E$

substituting values

$18.5 - 3.569 < \mu < 18.5 + 3.569$

$14.93 < \mu < 22.069$

8 0

2 years ago