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Leokris [45]
2 years ago
10

Determine whether each pair of actions results in independent or dependent events.

Mathematics
1 answer:
Norma-Jean [14]2 years ago
8 0

Answer h:

Step-by-step explanation:

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Choose the equation that represents the line passing through the point (−2, −3) with a slope of −6.
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We’re already at -3 (y) and the slope is negative so the y intercept is < -3. X is -2 and we need to find the y when x is 0. -2 is 2 away from 0 and 6 (the slope) times 2 is 12. -3 - 12 = - 15
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An artisan wants to split his equilateral triangular-shaped piece of glass into four equally sized pieces as part of a window de
jeka94

The triangle QPR having inscribed triangle STU will allow the artisan to divided his glass piece into four equal triangular pieces.

In order to divide an equilateral triangle into four equal triangular glass pieces, the artisan must;

  • Take S as the mid-point on PA, T as the mid-point on PR, and U as the mid-point on QR. Thus, S, T, and U are the three mid-points on each side of the equilateral triangle QPR.
  • Now, by joining these mid-points S, T, and U, four equal triangles are made(as shown in the figure).

Since the triangle is equilateral,

PQ = QR = RP

Mid-point divides the lines into equal parts. So,

PS = SQ = QU = UR = RT = TP

Thus, it is proved that

ΔPST = ΔSTU = ΔTUR = ΔQSU

Learn more about 'Equilateral Triangle' here:

brainly.com/question/2855144

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85 is what percent of 170?
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Two adjacent sides of a parallelogram are 6mm and 10mm respectively, and they form an angle measuring 60. Find the area of the p
Snowcat [4.5K]

Answer:

51.96 mm² approximately

Step-by-step explanation:

the first thing you should know is that the area of a rectangle is base*height sin of (

the included angle i.e

Arectangle= bh sin90° since all angles of a rectangle are equal then the included angle is 90°

<em>Arectangle= bh sin90° since sin90 is 1 we simply use the equation bh because multiplying bh by one is bh. bearing this in mind , the area of the parallelogram can be calculated as:</em>

Aparallelogram= bh sin of sin of the included angle

Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°

Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°Aparallelogram=60mm² * 0.866

Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°Aparallelogram=60mm² * 0.866Aparallelogram=51.96 mm² approximately

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2 years ago
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