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iVinArrow [24]
2 years ago
10

The force exerted on the tires of a car that directly accelerate it along a road is exerted by the

Physics
1 answer:
azamat2 years ago
7 0

The force exerted on the tires of a car that directly accelerate it along a road is exerted by the road friction.

<h3>What is force?</h3>

Force is defined as the product of mass and acceleration of an object.

Friction is defined as the force that resists the movement of an object over another.

Therefore, the force exerted on the tires of a car that directly accelerate it along a road is exerted by the road friction.

Learn more about force here:

brainly.com/question/12970081

#SPJ12

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Your own car has a mass of 2000. Kg if your car produces a force of 5000 N how fast will it accelerate?
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F = m*a
5000 = 2000 * x
5000/2000 = x
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1.Convert 340 cm into m *(answer=0.34m)
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Answer:

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<em>3</em><em>4</em><em>0</em><em>c</em><em>m</em><em>-</em><em>x</em>

<em>3</em><em>4</em><em>0</em><em>/</em><em>100</em>

<em>=</em><em>3</em><em>.</em><em>4</em>

<em>the </em><em>answer </em><em>is </em><em>supposed</em><em> to</em><em> be</em><em> </em><em>3</em><em>.</em><em>4</em><em>,</em><em> maybe</em><em> </em><em>there's</em><em> </em><em>a </em><em>mistake</em><em> </em><em>with </em><em>the </em><em>question</em><em> </em><em>or </em><em>the </em><em>answer</em>

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<em>mass×</em><em>g</em><em>r</em><em>a</em><em>v</em><em>i</em><em>t</em><em>y</em><em>,</em><em>in </em><em>this </em><em>case </em><em>the </em><em>mass </em><em>is </em><em>7</em><em>5</em><em>k</em><em>g</em><em> </em><em>and </em><em>the </em><em>gravity </em><em>is </em><em>9</em><em>.</em><em>8</em>

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An emf is induced in response to a change in magnetic field inside a loop of wire. Which of the following changes would increase
goldenfox [79]

Answer:

changing the magnetic field more rapidly

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8 0
3 years ago
(1 point) A projectile is fired from ground level with an initial speed of 600 m/sec and an angle of elevation of 30 degrees. Us
konstantin123 [22]

Answer:

(a) The range of the projectile is 31,813.18 m

(b) The maximum height of the projectile is 4,591.84 m

(c) The speed with which the projectile hits the ground is 670.82 m/s.

Explanation:

Given;

initial speed of the projectile, u = 600 m/s

angle of projection, θ = 30⁰

acceleration due to gravity, g = 9.8 m/s²

(a) The range of the projectile in meters;

R = \frac{u^2sin \ 2\theta}{g} \\\\R = \frac{600^2 sin(2\times 30^0)}{9.8} \\\\R = \frac{600^2 sin (60^0)}{9.8} \\\\R = 31,813.18 \ m

(b) The maximum height of the projectile in meters;

H = \frac{u^2 sin^2\theta}{2g} \\\\H = \frac{600^2 (sin \ 30)^2}{2\times 9.8} \\\\H = \frac{600^2 (0.5)^2}{19.6} \\\\H = 4,591.84 \ m

(c) The speed with which the projectile hits the ground is;

v^2 = u^2 + 2gh\\\\v^2 = 600^2 + (2 \times 9.8)(4,591.84)\\\\v^2 = 360,000 + 90,000.064\\\\v = \sqrt{450,000.064} \\\\v = 670.82 \ m/s

5 0
3 years ago
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