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Norma-Jean [14]
4 years ago
13

A light bulb will glow when electrons flow through it. As the electron flow increases, the brightness increases as well. A stude

nt hooks up two circuits containing three light bulbs in each circuit. In one circuit the lights are connected in series and in the other circuit the lights are hooked up in parallel.
If you could only see the lights in the circuit and the wires were covered from view, how could you determine the type of circuit the lights are arranged in?

A) If all the lights are equal brightness, it is a series circuit.
B) If all the lights are equal brightness, it is a parallel circuit.
C) Unscrew one light, if the others remain on it is a series circuit.
D) Unscrew one light, if the others remain on it is a parallel circuit.
Physics
2 answers:
Inga [223]4 years ago
6 0
The correct answer is: <span>Unscrew one light, if the others remain on it is a parallel circuit.</span>
Juliette [100K]4 years ago
3 0

The answer on USATESTPREP is D

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Answer : F=2808\times 10^{-11}\ N

Explanation :

It is given that,

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Using the relation as :

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Magnetic force is ,

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F=2808\times 10^{-11}\ N

Using Right hand thumb rule, the direction of force is in the plane perpendicular to the velocity and the magnetic field i.e. -\hat{k}.

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4 years ago
An electric heater is rated at 1400 W, a toaster is rated at 1150 W, and an electric grill is rated at 1560 W. The three applian
gayaneshka [121]

Answer:

The current in the heater is 12.5 A

Explanation:

It is given that,

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All three appliances are connected in parallel across a 112 V emf source. We need to find the current in the heater. We know that in parallel combination of resistors the current flowing in every branch of resistor divides while the voltage is same.

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I_1=\dfrac{1400\ W}{112\ V}

I_1=12.5\ A

So, the current in the heater is 12.5 A. Hence, this is the required solution.  

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