Thank you for posting your Physics question here. I hope the answer helps. Upon calculating the ramp with the horizontal the answer is 20.49 Deg. Below is the solution:
Y = 7 m.
<span>r = 20 m. </span>
<span>sinA = Y/r = 7/20 = 0.35. </span>
<span>A = 20.49 Deg.</span>
Answer:
Thorium 227 (also known as Radioactinium)
The average thickness of a sheet of the paper is 0.1 mm.
The number of ice blocks that can be stored in the freezer is 80 blocks of ice.
<h3>Average thickness of a sheet of the paper</h3>
The average thickness of a sheet of the paper is calculated as follows;
average thickness = 6 mm/60 sheets = 0.1 mm /sheet
Thus, the average thickness of a sheet of the paper is 0.1 mm.
<h3>Volume of each block of ice</h3>
Volume = 10 cm x 10 cm x 4 cm
Volume = 400 cm³
<h3>Volume of the freezer</h3>
Volume = 40 cm x 40 cm x 20 cm = 32,000 cm³
<h3>Number of ice blocks that can be stored</h3>
n = 32,000 cm³/400 cm³
n = 80 blocks of ice
Thus, the number of ice blocks that can be stored in the freezer is 80 blocks of ice.
Learn more about average thickness here: brainly.com/question/24268651
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By definition, the gain in PE (potential energy) is
ΔPE = m*g*h
Given:
mg = 40 N (Note that m*g = weight)
h = 5 m
ΔPE = (40 N)*(5 m) =200 J
Answer: 200 J
Answer:
in oil film λ = 303.57 10⁻⁹ m
in the water film λ = 319.55 10⁻⁹ m
Explanation:
When electromagnetic radiation reaches a material, its propagation is by a process that we call absorption and reflection,
when light reaches a surface it has a mass much greater than the mass of the photons (m = 0), therefore there is an elastic collision where the frequency does not change, due to the speed of light in the material medium changes, therefore the only possibility is that the wavelength in the material changes, to maintain the relationship
v = λ f
in the void we have
c = λ₀ f
we divide the two expression
c / v = λ₀ / λ
the refractive index is
n = c / v
n = λ₀ /λ
λ = λ₀ / n
let's calculate
in oil film
λ = 425 10⁻⁹ / 1.40
λ = 303.57 10⁻⁹ m
in the water film
λ = 425 10⁻⁹ / 1.33
λ = 319.55 10⁻⁹
those wavelengths are in the ultraviolet
