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laila [671]
3 years ago
14

How many significant digits are in the measurement 50.003010 nm?

Physics
2 answers:
masha68 [24]3 years ago
8 0

Answer:

There are 15 significant digits

Explanation:

50.00301 nm = 0.0000000500301

Counting the figures makes it 15

Lynna [10]3 years ago
5 0

Answer:

Significant digits = 8

Explanation:

Significant digits in a number which is more than 1 and if the number if having decimal in it then as per the rule all the digits present in the number must be significant digit

for an example we will say

1.00 = 3 significant figures

so in this way for all such kind of numbers we have to count all digits in it

so here given number is more than 1 and it contains the decimal in it

so we will say

50.003010 nm = 8 significant figures

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Why silicon have large forward current as compared to germanium?​
Iteru [2.4K]

Answer:

The structure of Germanium crystals will be destroyed at higher temperature. However, Silicon crystals are not easily damaged by excess heat. Peak Inverse Voltage ratings of Silicon diodes are greater than Germanium diodes. Si is less expensive due to the greater abundance of element.

4 0
3 years ago
The combination of all forces that act on an object are (2 points)
qaws [65]

Answer:

A) The net force

Explanation:

If two forces of equal strength act on an object in opposite directions, the forces will cancel, resulting in a net force of zero and no movement.

5 0
3 years ago
If sulfur 34 undergoes alpha decay, what will I become?
ikadub [295]
It will decay into Silicon-30. Because alpha particles are 2 protons and 2 neutrons with an atomic mass of 4, you minus sulfur's atomic number by 2 and get silicon. And the atomic mass is 34 - 4 which equals 30.
3 0
4 years ago
If half of the weight of a flatbed truck is supported by its two drive wheels, what is the maximum acceleration it can achieve o
Scilla [17]

Answer:

Maximum acceleration will be equal to 3.43m/sec^2

Explanation:

We have given coefficient of kinetic friction \mu _k=0.7

And coefficient of static friction \mu _s=1

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When truck moves maximum force will be equal to F=\mu _kmg

It is given that half of the weight is supported by its drive wheels

So force required =\frac{\mu _kmg}{2}

From newtons law maximum acceleration will be equal to a=\frac{\frac{\mu _kmg}{2}}{m}=\frac{\mu _kg}{2}=\frac{0.7\times 9.8}{2}=3.43m/sec^2

8 0
3 years ago
Its not b...................
vladimir1956 [14]

sir what's the question you have all you wrote is it's not b

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