6. What disadvantages or pitfalls might be associated with using a fa ce book classroom page? Name at least two and discuss why
1 answer:
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(a)
The total mechanical energy of the space probe must be constant, so we can write:
(1)
where
is the kinetic energy at the surface, when the probe is launched
is the gravitational potential energy at the surface
is the final kinetic energy of the probe
is the final gravitational potential energy
Here we have
at the surface, (radius of the planet),
(mass of the planet) and m=10 kg (mass of the probe), so the initial gravitational potential energy is
At the final point, the distance of the probe from the centre of Zero is
so the final potential energy is
So now we can use eq.(1) to find the final kinetic energy:
(b)
The probe reaches a maximum distance of
which means that at that point, the kinetic energy is zero: (the probe speed has become zero):
At that point, the gravitational potential energy is
So now we can use eq.(1) to find the initial kinetic energy:
The rms voltage output of the generator is 1.94 × 10⁻ ⁵ V.
RMS is an acronym for root mean squared. An RMS value is more than just the "amount of AC power that causes the same heating impact as an analogous DC power" or something along those lines.
No. of loop = 795
Diameter of the coil = 10.5 cm
Radius of the coil = 5.25 cm
Magnetic Field, B = 0.45 T
Time, t = 70.0 rev/s
Where,
N = No. of loop
A = Area of the coil
B = Magnetic Field
= Voltage rms
Area of the coil = πr²
= 86.57 cm²
w = 2π/t
=( 2 × 3.141)/70.0
= 0.089
Therefore, the rms voltage output of the generator is 1.94 × 10⁻ ⁵ V.
Learn more about rms voltage here:
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