All categories

4 years ago

What are the three ways resources are classified?

Chemistry

1 answer:

Korvikt [17]4 years ago

4 0

Answer:

On the basis of ownership, distribution, durabilities.

Explanation:

In 1933, the concept of resources was given Zimmerman as a resource signifies possibility and may b a means to an end. According to him resources satisfy human wants and needs, having two important functions of utility and ability.

Based on durability, they are either Fund or exhaustible resources. These get destroyed after use. Flow or inexhaustible resource remains unchanged even after continuous use like reiver, sea, and land.

Based on ownership, they are International means used by the global population. National resource means used by one nation in one country. And individual searches money or property resources etc.

And based on availability they are Ubiquitous and localized .like sunshine and the air is available everywhere.

You might be interested in

Cu+k.HNO3 --> Cu(No3)2+..........+...........

pentagon [3]

Answer:

Cu + HNO3 → Cu(NO3)2 + H2O + NO2

Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2 (balanced equation)

4 0

3 years ago

A solution is prepared by dissolving 0.5636 g oxalic acid (H2C2O4) in enough water to make 100.0 mL of solution. A 10.00-mL aliq

zepelin [54]

Answer:

The final molarity of the diluted oxalic acid solution is 0.002504 M

Explanation:

Step 1: Data given

Mass of oxalic acid (H2C2O4) = 0.5636 grams

Volume of the solution = 100.0 mL = 0.100 L

A 10 ml of this solution diluted in 250 ml of solution.

Molecular weight of H2C2O4 = 90.03 g/mol

Step 2: Calculate initial moles of H2C2O4

Moles H2C2O4 = mass / molar mass

Moles H2C2O4 = 0.5636 grams / 90.03 g/mol

Moles H2C2O4 = 0.00626 moles

Step 3: Calculate molarity of the solution

Molarity = moles / volume

Molarity = 0.00626 moles / 0.100 L

Molarity = 0.0626 M

Step 4: Calculate moles of a 10.00 mL aliquot

Moles = 0.0626 M * 0.010 L

Moles = 0.000626 moles

Step 5: Calculate the new molarity

Molarity = 0.000626 moles / 0.250 L

Molarity = 0.002504 M

The final molarity of the diluted oxalic acid solution is 0.002504 M

6 0

3 years ago

A sample was prepared by mixing 18. ml of 3.00 x 10^-3 m crystal violet (cv) with 2.00 ml of 0.250 m naoh. calculate the resulti

Aleks [24]

Answer : The resulting concentrations of CV and NaOH are 0.0027 M and 0.025 M respectively.

Explanation :

Step 1 : Find moles of crystal violet and NaOH.

The molarity formula is

$Molarity = \frac{mol}{L}$

Molarity of crystal violet = $3.00 \times 10^{-3} = \frac{mol (CrystalViolet)}{L}$

The volume of crystal violet solution is 18 mL which is 0.018 L.

Moles of crystal violet = $3.00 \times 10^{-3} \times 0.018 = 5.4 \times 10^{-5}$

Moles of crystal violet = 5.4 x 10⁻⁵

Moles of NaOH = $Molarity \times L = 0.250 \times 0.00200 = 5.00 \times 10^{-4}$

Moles of NaOH = 5.00 x 10⁻⁴

Step 2 : Find total volume of the solution

The total volume of the solution after mixing NaOH and crystal violet is

0.018 L + 0.00200 = 0.020 L

Step 3 : Use molarity formula to find final concentrations

Molarity of crystal violet = $\frac{mol(CrystalViolet)}{Total Volume(L) } = \frac{5.4 \times 10^{-5}}{0.020} = 2.7 \times 10^{-3}$

Final concentration of CV = 0.0027 M

Molarity of NaOH= $\frac{mol(NaOH)}{Total Volume(L) } = \frac{5.00 \times 10^{-4}}{0.020} = 0.025 \times 10^{-3}$

NaOH is a strong base and dissociates completely as follows.

$NaOH (aq) \rightarrow Na^{+} (aq) + OH^{-} (aq)$

The mole ratio of NaOH and OH⁻ is 1:1 . Therefore the concentration of OH⁻ is same as that of NaOH.

Concentration of OH⁻ = 0.025 M

8 0

3 years ago

5.0 gram of anhydrous calcium carbonate is reacted with an excess of dilute nitric acid. if the reaction is carried out at 25 de

Aneli [31]

Answer:

I don’t know

Explanation:

6 0

3 years ago

What is the name for SO2

Tanzania [10]

Sulphur Dioxide. Toxic. Don't eat it.

7 0

4 years ago