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Zinaida [17]
3 years ago
10

What is the weight of an object (mass = 60 kilograms) on Mars, where the acceleration due to gravity is 3.75 meters/second2?

Physics
1 answer:
enot [183]3 years ago
5 0

Answer:

Weight of an object = 225 newtons

Explanation:

Given:

Mass = 60 kilograms

Acceleration due to gravity = 3.75 m/s²

Find:

Weight of an object

Computation:

Weight of an object = Mass x Acceleration due to gravity

Weight of an object = 60 x 3.75

Weight of an object = 225 newtons

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Tema [17]

Answer:

33.6\times10^{-4}}\text{ m} = 3.36 mm

Explanation:

From Ohm's law,

V = IR (Voltage = Current * Resistance)

R = \dfrac{V}{I}

The geometric definition of resistance is

R = \rho\dfrac{l}{A}

where \rho is the resistivity of the material, l  and A are the length and cross-sectional area, respectively.

A = \rho\dfrac{l}{R}

A = \rho\dfrac{l\timesI}{V}

Since the wire is assumed to have a circular cross-section, its area is given by

A = \pi\dfrac{d^2}{4} where d is the diameter.

\pi\dfrac{d^2}{4} = \rho\dfrac{l\timesI}{V}

d = \sqrt{\dfrac{4\rho l I}{\pi\times V}}

Resistivity of copper = 1.68\times10^{-8}. With these and other given values,

d = \sqrt{\dfrac{4\times1.68\times10^{-8}\times1.5\times290}{3.14\times 0.55}}

d = \sqrt{1128.43\times10^{-8}}

d = 33.6\times10^{-4} \text{ m}

5 0
3 years ago
Calculate the amount of heat transferred when 710 grams of water warms from an initial temperature of 4.0 ºC to a final temperat
tigry1 [53]

Answer:

Q = 62383.44 Joules

Explanation:

Given that,

Mass of water, m = 710 gm

Initial temperature of water, T_i=4^{\circ} C

Final temperature of water, T_f=25^{\circ} C

The specific heat capacity of liquid water is, c=4.184\ J/g\ ^oC

Heat transferred is given by :

Q=mc(T_f-T_i)

Q=710\times 4.184\times (25-4)

Q = 62383.44 Joules

So, the amount of heat transferred is 62383.44 Joules. Hence, this is the required solution.

3 0
3 years ago
A satellite in outer space is moving at a constant velocity of 20.5 m/s in the +y direction when one of its on board thruster tu
Katyanochek1 [597]

Answer:

a)  V_f = 25.514 m/s

b)  Q =53.46 degrees CCW from + x-axis

Explanation:

Given:

- Initial speed V_i = 20.5 j m/s

- Acceleration a = 0.31 i m/s^2

- Time duration for acceleration t = 49.0 s

Find:

(a) What is the magnitude of the satellite's velocity when the thruster turns off?

(b) What is the direction of the satellite's velocity when the thruster turns off? Give your answer as an angle measured counterclockwise from the +x-axis.

Solution:

- We can apply the kinematic equation of motion for our problem assuming a constant acceleration as given:

                                   V_f = V_i + a*t

                                   V_f = 20.5 j + 0.31 i *49

                                   V_f = 20.5 j + 15.19 i

- The magnitude of the velocity vector is given by:

                                   V_f = sqrt ( 20.5^2 + 15.19^2)

                                   V_f = sqrt(650.9861)

                                  V_f = 25.514 m/s

- The direction of the velocity vector can be computed by using x and y components of velocity found above:

                                 tan(Q) = (V_y / V_x)

                                 Q = arctan (20.5 / 15.19)

                                 Q =53.46 degrees

- The velocity vector is at angle @ 53.46 degrees CCW from the positive x-axis.

4 0
3 years ago
How many feet are in a mile
klemol [59]

Hello There!

There are 5,280 feet in 1 mile.

Have A Great Day!

7 0
3 years ago
Read 2 more answers
a 100 kg gymnast comes to a stop after tumbling. her feet do -5000J of net work to stop her. Use the work-kinetic energy theorem
VikaD [51]
W=ΔKE , W=-5000j
KEinitial=(1/2)mv² , KEfinal=0j 
ΔKE=-(1/2)mv²
-5000=-(1/2)(100kg)v²
v=10 m/s

6 0
3 years ago
Read 2 more answers
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