Answer:
the value of vA that will allow the car to coast in neutral so as to just reach the top of the 150 m high hill at B with vB = 0 is 31.3 m/s
Explanation:
given information
car's mass, m = 1200 kg
= 100 m
=
= 150 m
= 0
according to conservative energy
the distance from point A to B, h = 150 m - 100 m = 50 m
the initial speed
final speed = 0
thus,
² = ² - 2 g h
0 = ² - 2 g h
² = 2 g h
= √2 g h
= √2 (9.8) (50)
= 31.3 m/s
Answer:
All we need to know for this is SUVAT equations. There are 5 SUVAT equations you need to learn. S = distance, U = initial velocity, V = final velocity, A = acceleration, T = time V= U + AT V^2 = U^2 + 2AS S = UT + 1/2AT^2 S = VT -
Explanation:
don't now if this hellps or not
Answer:
h = 206.4 m
range = 515.9 m
Explanation:
from the question we are given the following:
initial velocity (u) = 75 m/s
angle above surface = 58 degrees
acceleration due to gravity (g) = 9.8 m/s^{2}
find the maximum height (h) and the horizontal distance
maximum height (h) = 
h = 
h = 206.4 m
the horizontal distance here is the range
range = 
range = 
range = 515.9 m
A question you can gather from this experiment is figuring out the distance traveled by the car, and how far it went. A simple solve of X equation could be used.
B, is the answer to the question
