1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
cricket20 [7]
3 years ago
5

A satellite in outer space is moving at a constant velocity of 20.5 m/s in the +y direction when one of its on board thruster tu

rns on, causing an acceleration of 0.310 m/s^2 in the +x direction. The acceleration lasts for 49.0 s, at which point the thruster turns off.
(a) What is the magnitude of the satellite's velocity when the thruster turns off?
(b) What is the direction of the satellite's velocity when the thruster turns off? Give your answer as an angle measured counterclockwise from the +x-axis.
Physics
1 answer:
Katyanochek1 [597]3 years ago
4 0

Answer:

a)  V_f = 25.514 m/s

b)  Q =53.46 degrees CCW from + x-axis

Explanation:

Given:

- Initial speed V_i = 20.5 j m/s

- Acceleration a = 0.31 i m/s^2

- Time duration for acceleration t = 49.0 s

Find:

(a) What is the magnitude of the satellite's velocity when the thruster turns off?

(b) What is the direction of the satellite's velocity when the thruster turns off? Give your answer as an angle measured counterclockwise from the +x-axis.

Solution:

- We can apply the kinematic equation of motion for our problem assuming a constant acceleration as given:

                                   V_f = V_i + a*t

                                   V_f = 20.5 j + 0.31 i *49

                                   V_f = 20.5 j + 15.19 i

- The magnitude of the velocity vector is given by:

                                   V_f = sqrt ( 20.5^2 + 15.19^2)

                                   V_f = sqrt(650.9861)

                                  V_f = 25.514 m/s

- The direction of the velocity vector can be computed by using x and y components of velocity found above:

                                 tan(Q) = (V_y / V_x)

                                 Q = arctan (20.5 / 15.19)

                                 Q =53.46 degrees

- The velocity vector is at angle @ 53.46 degrees CCW from the positive x-axis.

You might be interested in
What is the maximum value the string tension can have before the can slips? The coefficient of static friction between the can a
Naya [18.7K]

Answer:

T= 38.38 N

Explanation:

Here

mass of can = m = 3 kg

g= 9.8 m/sec2

angle θ = 40°

From figure we see the vertical and horizontal component of tension force T

If the can is to slip - then horizontal component of tension force should become equal to force of friction.

First we find force of friction

Fs= μ R

where

μ = 0.76

R = weight of can = mg = 3 × 9.8 = 29.4 N

Now horizontal component of tension

Tx= T cos 40 = T× 0.7660  N

==>T× 0.7660 = 29.4

==> T= 38.38 N

8 0
3 years ago
Can anyone help me with this
Murrr4er [49]

Answer:

event s

Explanation:

the cow gets oxygen from the tree and proceeds to respirate.

8 0
3 years ago
What is the name of the hair-like structures on sponge cells that move back and forth to help move water, nutrients, and waste t
Dima020 [189]
I think it's B. Flagella

5 0
3 years ago
Read 2 more answers
Why the dogs lays down next to the wood stove? Is it radiation,convection,conduction?
malfutka [58]
Radiation because it radiates the heat in there body therefore making them hot.

4 0
3 years ago
1.Suppose someone pulls a cart up a ramp a distance of 85cm along the ramp with a force of 15N.
Drupady [299]

1. 12.75 J

Assuming that the force applied is parallel to the ramp, so it is parallel to the displacement of the cart, the work done by the force is

W=Fd

where

F = 15 N is the magnitude of the force

d = 85 cm = 0.85 m is the displacement of the cart

Substituting in the formula, we get

W=(15 N)(0.85 m)=12.75 J


2. 10.6 N

In this part, the cart reaches the same vertical height as in part A. This means that the same work has been done (because the work done is equal to the gain in gravitational potential energy of the object: but if the vertical height reached is the same, then the gain in gravitational potential energy is the same, so the work done must be the same).

Therefore, the work done is

W=Fd=12.75 J

However, in this case the displacement is

d = 120 cm = 1.20 m

Therefore, the magnitude of the force in this case is

F=\frac{W}{d}=\frac{12.75 J}{1.20 m}=10.6 N

3 0
2 years ago
Other questions:
  • Select the true statements: check all that apply check all that apply oxidizing agents can convert co into co2. a reducing agent
    15·1 answer
  • An antique carousel that’s powered by a large electric motor undergoes constant angular acceleration from rest to full rotationa
    8·1 answer
  • A sports car is advertised to be able to stop in a distance of 50.0 m from a speed is 99.0km/h. What is its acceleration in m/s2
    10·1 answer
  • What is a “plate” in geological terms
    6·1 answer
  • Do you wont to be friends
    9·1 answer
  • What gives an object gravity?
    11·1 answer
  • <img src="https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20.r3" id="TexFormula1" title="V = \frac{4}{3} \pi .r3
    11·1 answer
  • Kinetic Energy HELP! Brainly included
    14·1 answer
  • 1. The electromagnetic waves described in the reading are different in which two ways:
    10·1 answer
  • Who watching all star draft? Luka better get picked first ong
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!