Answer:
0.414 mole (3 sig. figs.)
Explanation:
Given grams, moles = mass/formula weight
moles in 18.2g CO₂(g) = 18.2g/44g/mole = 0.413636364 mole (calc. ans.)
≅ 0.414 mole (3 sig. figs.)
Answer : The limiting reagent is 
Solution : Given,
Moles of methane = 2.8 moles
Moles of = 5 moles
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 2 mole of react with 1 mole of 
So, 5 moles of react with 
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.
Hence, the limiting reagent is
The correct answer is neon
Adenine pairs with Thymine and Guanine pairs with Cytosine. I remember this by the car (C) goes in the garage (G). Then A and T are the only ones left, so they pair together.
If there is NO wind resistance, just plain math, this is the answer.
To get the answer you would divide 800 by 650.
800/650 = 1.230769231 (exactly)
That would translate to exactly <span>1 hour 13 minutes and 50 seconds </span>
