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Taya2010 [7]
3 years ago
11

5. Let's factorize the following numbers and express in exponential form16​

Mathematics
2 answers:
timama [110]3 years ago
7 0

Answer:

2^4

Step-by-step explanation:

16 = 2x2x2x2 = 2 to the power of 4

nasty-shy [4]3 years ago
5 0

Answer:

2^4

Step-by-step explanation:

Hope this helped have an amazing day!

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Add 7/10 + 1/6 enter your answer below as a fraction in lowest terms, using the slash(/) as the fraction bar
san4es73 [151]

Answer:

13/15

Step-by-step explanation:

pls mark me brainliest

4 0
3 years ago
Biruk wants to buy a book for $15.25 and a book for $4.85. He wants to pay with one $20 bill. Use estimation to decide if this i
ycow [4]
First round 15.25 to 15.30 and round 4.85 to 4.90 and then add you get 21.20  no it is not reasonable and you round to the decimal ones
8 0
3 years ago
Read 2 more answers
Write the STANDARD FORM of the equation through the point (4,-4) witha slope of -2.
boyakko [2]

The general equation of line with the slope "m" and passing points (a,b) is :

y - b = m (x -a)

In the given question:

Slope m = -2, passing points (a,b) = (4,-4)

Substitute the value of a = 4, b = -4 in the general equation of line

\begin{gathered} y-b=m(x-a) \\ y-(-4)=(-2)(x-4) \\ y+4=-2(x-4) \\ y+4=-2x+8 \\ y+2x=8-4 \\ 2x+y=4 \end{gathered}

The equation with the slope -2 and passing points (4,-4) is 2x + y = 4

Answer : 2x + y = 4

8 0
1 year ago
The equation of a line is -6x-2y=-18<br> What is the x-intercept of the line?
Fed [463]

 -6x - 2y = -18

-6x - 2(0) = -18

   -6x - 0 = -18

        -6x = -18

         -6      -6

           x = 3

hope this helps :)

8 0
3 years ago
Read 2 more answers
Solve the equation x+3/x-4 = x-5/x+4
Serga [27]

Answer:

\large\boxed{x=\dfrac{1}{2}}

Step-by-step explanation:

\dfrac{x+3}{x-4}=\dfrac{x-5}{x+4}\\\\\text{Domain:}\ x-4\neq0\ \wedge\ x+4\neq0\\\\x\neq4\ \wedge\ x\neq-4\\\\D:x\in\mathbb{R}-\{-4,\ 4\}

\dfrac{x+3}{x-4}=\dfrac{x-5}{x+4}\qquad\text{cross multiply}\\\\(x+3)(x+4)=(x-4)(x-5)\qquad\text{use FOIL}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(x)(x)+(x)(4)+(3)(x)+(3)(4)=(x)(x)+(x)(-5)+(-4)(x)+(-4)(-5)\\\\x^2+4x+3x+12=x^2-5x-4x+20\qquad\text{combine like terms}\\\\x^2+(4x+3x)+12=x^2+(-5x-4x)+20\\\\x^2+7x+12=x^2-9x+20\qquad\text{subtract}\ x^2\ \text{from both sides}\\\\7x+12=-9x+20\qquad\text{subtract 12 from both sides}\\\\7x=-9x+8\qquad\text{add}\ 9x\ \text{to both sides}\\\\16x=8\qquad\text{divide both sides by 16}\\\\x=\dfrac{8}{16}\\\\x=\dfrac{8:8}{16:8}\\\\x=\dfrac{1}{2}\in D

7 0
3 years ago
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