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2 years ago

Which chemical equation represents the reaction of an Arrhenius acid and an Arrhenius base?

2 answers:

6 0

The chemical equation that represents the reaction of an Arrhenius acid and an Arrhenius base is 1) HC2H3O2 (aq) + NaOH (aq) ---> NaC2H3O2 (aq) + H2O (I)

Xelga [282]2 years ago

5 0

Answer : The correct option is, (1)

Explanation :

According to the Arrhenius acid-base concept,

Arrhenius acid is a species that produces $H^+$ ion in an aqueous solution and Arrhenius base is a species that produces $OH^-$ ion in an aqueous solution.

From the given options, option 1 chemical equation represents the reaction of an Arrhenius acid and an Arrhenius base. In this reaction, $HC_2H_3O_2$ produces $H^+$ ion in an aqueous solution and act as an Arrhenius acid, $NaOH$ produces $OH^-$ ion in an aqueous solution and act as an Arrhenius base.

While the other options does not represents the reaction of an Arrhenius acid and an Arrhenius base.

Reaction 2 is an example of combustion reaction.

Reaction 3 is an example of single-displacement reaction.

Reaction 4 is an example of double-displacement reaction.

Hence, the correct option is, (1)

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The value of K at constant temperature depends on the amounts of reactants and products that are mixed together initially. A lar

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Answer:

a) K = [ CO2(g) ]

⇒ the [ CaCO3(s) ] does not appear in the denominator of the equilibrium constant, as it is a pure solid substance.

b) Kp = K (RT)∧Δn

⇒ the values of K and Kp are not the same

c) K >> 1, The reaction has a high yield and is said to be shifted to the right. then the rate of the forward reaction is greater than the rate of the reverse reaction at equilibrium.

Explanation:

a) CaCO3(s) ↔ CaO(s) + CO2(g)

⇒ K = [ CO2(g) ]

∴ the [ CaCO3(s) ] does not appear in the denominator of the equilibrium constant, as it is a pure solid substance.

b) H2(g) + F2(g) ↔ 2 HF(g)

⇒ K = [ HF(g) ] ² / [ F2(g) ] * [ H2(g) ]

⇒ Kp = PHF² / PF2 * PH2

for ideal gas:

PV = RTn

⇒ P = n/V RT = [ ] RT

⇒ Kp = K (RT)∧Δn

⇒ the values of K and Kp are not the same.

c) K >> 1, The reaction has a high yield and is said to be shifted to the right. then the rate of the forward reaction is greater than the rate of the reverse reaction at equilibrium.

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2 years ago

A chemist prepares a solution of sodium carbonate by measuring out of sodium carbonate into a volumetric flask and filling the f

Vadim26 [7]

Answer:

The correct answer will be " $9.45\times 10^{-5} \ mol/L$ ".

Explanation:

We have:

Moles of solute (Na₂Co₃) = $18.9 \mu \ mol$

= $18.9\times 10^{-6}$

$1 \mu \ mol$ = $10^{-6} \ mol$

Now,

The volume of the solution will be:

⇒ $0.200 \ L$

∴ ${1 \ mL=0.001 \ L}$

The formula to find the concentration will be:

⇒ $Concentration = \frac{moles \ of \ solute \ (mol)}{Volume \ of \ solution \ (L)}$

On substituting the given values, we get

⇒ $=\frac{18.9\times 10^{-6}}{0.200}$

⇒ $=9.45\times 10^{-5} \ mol/L$

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